2
$\begingroup$

For real numbers $t>0$ and $x$, let $f(x)=\sum_{k=1}^Ne^{ikx}$ and $g(t)=\int_{-t}^{t}\lvert f(x)\rvert^2dx$. Then $g(\pi)=\int_{-\pi}^{\pi}\lvert f(x)\rvert^2dx=2\pi N$.

I want to know is there any results about the value of $g(t)$ for small $t$ relevant to $N$. In particular, what is the asymptotic behavior (or just the order) of the value $g\left(\frac{\pi\log N}{N}\right)$?

$\endgroup$
0

1 Answer 1

5
$\begingroup$

Using the formula for the sum of the first $n$ terms of a geometric series, we have
$$|f(x)|^2=\frac{\sin^2(Nx/2)}{\sin^2(x/2)}$$ and hence for $t\downarrow 0$ $$g(t)=2\int_0^t |f(x)|^2\,dx =2\int_0^t \frac{\sin^2(Nx/2)}{\sin^2(x/2)}\,dx \\ \sim8\int_0^t \frac{\sin^2(Nx/2)}{x^2}\,dx =4N\,\int_0^{Nt/2} \frac{\sin^2 u}{u^2}\,du \sim2\pi N=g(\pi)$$ if $Nt\to\infty$. In particular, this asymptotic holds for $t=\frac{\pi\ln N}N$.

It also follows that $$g(t) \sim2\pi N=g(\pi)$$ whenever $t\in(0,\pi]$ varies so that $Nt\to\infty$.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .