7
$\begingroup$

Let $f : X\rightarrow Y$ be a proper flat morphism (of schemes) with connected fibers over a smooth projective curve $Y$ over $\mathbb{C}$. Let $X_{y_0}$ denote a smooth fiber over $y_0\in Y$.

If $f$ is smooth, then the topological Euler characteristic is multiplicative: $\chi(X) = \chi(Y)\cdot\chi(X_{y_0})$. In general, there is a formula for the topological Euler characteristic which includes some correction terms for the singular fibers: $$\chi(X) = \chi(Y)\chi(X_{y_0}) + \sum_{y\in Y}(\chi(X_y) - \chi(X_{y_0})$$

Does there exist an analogous formula for the holomorphic/algebraic Euler characteristic? I'm in particular interested in the case where $X\rightarrow Y$ is a family of curves over $Y$ (so $\dim X = 2$). To be precise, I'm looking for a formula for $\chi(X,\mathcal{O}_X)$ in terms of geometric invariants of $Y$ and some fibral data. By fibral data I mean geometric properties which are local on the base $Y$ (e.g. geometric invariants of fibers, monodromy around singular fibers acting on the cohomology of a smooth fiber...etc).

As a nonexample, Riemann-Roch relates this Euler characteristic to the intersection number of $X_{y_0}$ with $K - X_{y_0}$ (which can be understood locally on $Y$) plus $\chi(X,\mathcal{O}_X(X_{y_0}))$ (which does not appear to be local on $Y$).

Added in edit: To state a more precise question -- Is the holomorphic Euler characteristic $\chi(X,\mathcal{O}_X)$ determined by $Y$ and data which is local on $Y$? Stated another way, do there exist maps $f : X\rightarrow Y$ and $f' : X'\rightarrow Y$ (satisfying the above conditions) such that

  1. there is a covering in the etale topology $\{U_i\rightarrow Y\}_{i\in I}$ and isomorphisms $\phi_i : X_{U_i}\rightarrow X'_{U_i}$, and
  2. $\chi(X,\mathcal{O}_X)\ne \chi(X',\mathcal{O}_{X'})$.

Here I'm happy to assume that $X,X'$ are smooth over $\mathbb{C}$ (but I still want to allow singular fibers of $f,f'$). If it changes the answer, I'm also interested in the variation where $\{U_i\}$ is instead an open covering in the analytic topology. I am also interested in results where we assume that $X,X'$ are moreover general type. If the euler characteristic is not determined by $Y$ and data local on $Y$, then I'm also interested in any contraints such data might impose on $\chi(X,\mathcal{O}_X)$.

$\endgroup$
5
  • 2
    $\begingroup$ I am trying to understand how your "nonexample" is not an example. What kind of formula do you envision when $X$ equals $Y\times Z$ if you are not allowing $\chi(Z,\mathcal{O}_Z)$ as part of your formula? $\endgroup$ Apr 9, 2022 at 0:31
  • $\begingroup$ Are you willing to assume that $X$ (not $f$) is smooth? $\endgroup$ Apr 9, 2022 at 7:42
  • 1
    $\begingroup$ @JasonStarr I imagine $\chi(X_{y_0},\mathcal O_{X_{y_0}})$ would be allowed as it is 'fibral', but not $\chi(X,\mathcal O_X(X_{y_0}))$ as it is 'global' on $X$. $\endgroup$ Apr 9, 2022 at 14:12
  • $\begingroup$ @JasonStarr Remy is right - $\chi(X_{y_0},\mathcal{O}_{X_{y_0}})$ would be fine, but $\chi(X, \mathcal{O}_X(X_{y_0}))$ wouldn't be, unless it can somehow be expressed in terms of data which is local on $Y$. $\endgroup$
    – Will Chen
    Apr 9, 2022 at 15:09
  • $\begingroup$ @PiotrAchinger Sure, I'd be happy for an answer in the case of smooth $X$. $\endgroup$
    – Will Chen
    Apr 10, 2022 at 20:07

1 Answer 1

5
$\begingroup$

I'm not entirely sure what would constitute an answer. But here a few simple observations. Let me focus on what you seem be interested in, namely a projective family of connected curves over smooth projective curve $f:X\to Y$. Let me also assume $X$ smooth. Let $h$ be the genus of $Y$, and $g$ the genus of the general fibre. Then from the Leray spectral sequence, Riemann-Roch and Grothendieck duality $$\chi(\mathcal{O}_X)= (1-g)(1-h) - \deg R^1f_*\mathcal{O}_X=\chi(\mathcal{O}_Y)\chi(\mathcal{O}_{X_{y_0}})+\deg f_*\omega_{X/Y}$$ A theorem of Fujita then gives an inequality $$\chi(\mathcal{O}_X)\ge \chi(\mathcal{O}_Y)\chi(\mathcal{O}_{X_{y_0}})$$ which is something. To say more, one would need to compute $\deg f_*\omega_{X/Y}$. But I think this depends on more than local information at the bad fibres, which is what I think you are asking. The reason I say this, is that this degree can be positive and variable for Kodaira surfaces, which have no bad fibres at all. [Added Comment I guess there are various things called Kodaira surfaces. The ones I have in mind are of general type, and hence algebraic. See page 220 of Compact Complex Surfaces by Barth, Hulek, Peters and Van de Ven for further details.]

$\endgroup$
3
  • $\begingroup$ Somehow the point is that the Euler characteristic of a rank $n$ vector bundle is not just $n\chi(X,\mathcal O_X)$, but also depends on global data like the degree. By contrast (and somewhat to my surprise), for local systems the situation is much easier: $\chi(X,\mathcal L) = \operatorname{rk}(\mathscr L)\chi(X,\underline{\mathbf Q})$. $\endgroup$ Apr 10, 2022 at 23:29
  • $\begingroup$ Thank you for this! It looks like Kodaira surfaces are not algebraic? Do you know of an algebraic example? (I've also edited the question to make it more precise). $\endgroup$
    – Will Chen
    Apr 14, 2022 at 17:54
  • $\begingroup$ @WillChen Yes, I added more explanation. $\endgroup$ Apr 14, 2022 at 22:08

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.