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A similar question on MSE without answer.

Let $M, N$ be smooth manifolds such that $\partial N=\varnothing$. Let $A$ be a smoothly embedded submanifold of $N$ such that $\partial A\neq \varnothing$. Suppose, $f\colon M\to N$ be a smooth map with $f\pitchfork A,\ f\pitchfork \partial A$. In case $\partial M\neq \varnothing$, we also assume that the restriction $f\big|\partial M\to N$ is transverse to $A$.

Is it true that $f^{-1}(A)$ is a smoothly embedded submanifold of $M$ with $$\partial f^{-1}(A)=\begin{cases}f^{-1}(\partial A)&\text{ if }\partial M=\varnothing,\\ \big(f^{-1}(A)\cap \partial M\big)\cup f^{-1}(\partial A) &\text{ if }\partial M\neq \varnothing.\end{cases}$$

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  • $\begingroup$ This isn't quite true, since the pre-image may no longer be a manifold with boundary (when $M$ and $A$ have boundary). For example, it can be a manifold with cubical corners. $\endgroup$ Commented Mar 25, 2023 at 7:38

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