0
$\begingroup$

Let $E=C([0,1]^m,\mathbb{R}^n)$ where $K=[0,1]^m$ where $E$ has the compact convergence topology. Recall that for a function $f:[0,1]^m\rightarrow [0,1]^m$ the associated composition operator $C_f$ is defined by $$ \begin{aligned} C_f:E &\rightarrow E\\ g &\mapsto g\circ f. \end{aligned} $$ We recall that $C_f$ is call cylic if there is some $g^f\in E$ such that $\operatorname{span}\{g^f\circ f^n\}_{n=0}^{\infty}$ is dense in $E$.
Lastly, let $L(E)$ denote the space of bounded linear operators on $E$ with the weak operator topology.

Is the span of the set of composition operators $C_f$ for which $f$ is cylic, dense in $L(E)$? If yes, what about if it instead has the strong operator topology?

$\endgroup$
3
  • 3
    $\begingroup$ On the space $E$, a composition operator $C_f$ is never hypercyclic since it is always power-bounded. $\endgroup$ Commented Feb 13, 2022 at 10:17
  • $\begingroup$ Thanks for your response! I'm afraid I still don't understand the question, though. The set of all composition operators (no matter whether cyclic or not) is clearly not dense in $L(E)$. $\endgroup$ Commented Feb 14, 2022 at 20:43
  • 1
    $\begingroup$ @JochenGlueck Ah, I mean its span. Hmm, it seems this question has been plagued with typos. Hopefully it's polished now. $\endgroup$
    – ABIM
    Commented Feb 14, 2022 at 21:35

0

You must log in to answer this question.