Suppose I have two polynomials with real coefficients. Suppose I can perform any sort of preprocessing on them I want. I want to be able to pre-emptively say that the sum of the polynomials doesn't have any roots inside a given interval without doing any explicit calculations on the sum itself. False positives (that is, saying there aren't any roots when there are some) would be deal-breaking, but false negatives (reporting there might be roots when there aren't) would be acceptable.

Or to put it more explicitly:

All functions $p_x(t)$ have a form like:

$p_x(t) = a_{n,x} * t^n + a_{n-1, x} * t^{n-1} + ... + a_{1,x} * t + a_{0,x}$

We can define $p_3(t) = p_1(t) + p_2(t)$

I want to determine if $p_3(t)$ might have any roots inside a given interval $[t_{min}, t_{max}]$. But I want to do it only using properties of $p_1(t)$ and $p_2(t)$, their roots, etc. and not anything that would need me to calculate anything for $p_3(t)$, its roots, etc.

Any ideas on how to approach the problem?

EDIT: So some motivation of what I'm doing: I have a large set of polynomials that are related to the path of a point through space over time. I want to find polynomials that intersect sometime in the "near" future, but I don't want to have to do all $\frac{n*(n-1)}{2}$ polynomial-to-polynomial evaluations. So I'm trying to build a "broad phase" that only offers up pairs of polynomials to be solved in a "narrow phase" (ie: actual root finding) if they're "pretty close" to colliding. Whatever the algorithm for the broad phase is, it can't involve iterating over all the polynomial pairs or it defeats the point.

One sort of square-peg-round-hole solution would be to use something like bounding boxes around the polynomials and use a spatial partitioning tree to find where boxes overlap, and then do the root finding on those. But it doesn't handle cases very well where the time interval of interest is quite large, or especially if one of the interval ends is infinity or negative infinity.

So I wanted to explore it from another direction and see if I can come up with something that works better.