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The following question is inspired by Bill's nice unpublished result that the dual of a non separable Banach space is decomposable. (See the previous posts Decomposable Banach Spaces, Hereditarily indecomposable Banach spaces and Separable Quotient problem and A question related to the separable quotient problem.)

Definition: A dual Banach space $X^*$ is said to be $w^*$-HI if $\operatorname{dist} (S_Y,S_Z )= 0$ for every $Y$, $Z$ infinite dimensional $w^*$-closed subspaces of $X^*$. The space $X^*$ is said to be $w^*$-indecomposable if it is not the direct sum of two infinite dimensional $w^*$-closed subspaces.

Question I: Does there exist non separable $X$ such that $X^*$ is $w^*$-HI?

Question II: For $X$ HI is the second dual $X^{**}$ $w^*$-inecomposable?

There exists $X$ HI such that $X^*$ is non separable and $X^{**}= X \oplus l^2(2^N)$.

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  • $\begingroup$ What ist $S_Y$? $\endgroup$ Commented Jan 8, 2022 at 13:18
  • $\begingroup$ The unit sphere of $Y$. $\endgroup$
    – S Argyros
    Commented Jan 8, 2022 at 14:45
  • $\begingroup$ TeX note: please do not drop in and out of math mode in the middle of a formula. For example, write $X^{**} = X \oplus l^2(2^N)$ $X^{**} = X \oplus l^2(2^N)$, not $X^{**}$= $X$ $\oplus$ $l^2(2^N)$ $X^{**}$= $X$ $\oplus$ $l^2(2^N)$. (Notice the different appearance of symbols, and the difference in spacing.) I have edited accordingly. $\endgroup$
    – LSpice
    Commented Jan 8, 2022 at 21:06
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    $\begingroup$ @LSpice Thanks for improving the presentation $\endgroup$
    – S Argyros
    Commented Jan 9, 2022 at 10:43

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