2
$\begingroup$

Many theorems have the form : Premise(es) implies Conclusion(s)

Example A of wrongness:
There are many examples in which a theorem is stated without mentioning that part of the premise is not necessary to reach the conclusion.
Usually it is simple (and much better) to add a remark stating that the result is not sharp (ideally providing an example of weaker premise holding with the solution).

But there is another type of bias :

Added Note: Below composition means the AND of two relations ( for classical composition the transitivity does not compose! ( thanks to HenrikRüping remark).

Example B of wrongness:
Theorem 1 : The composition of 2 equivalence relations is an equivalence relation.
Or in fewer words : Equivalence relations are stable under composition.

Actually there is a much finer version of B :

Theorem A: For relations each of the following properties are stable under composition : Reflexive , Transitive , Symmetric.
By conjunction of the above we obtain:
Corollary B: Equivalence relations are stable under composition

Note: The second form is not only more precise but it also makes the mention "left as an easy exercise" more acceptable.

The "WRONG" notion:
I called theorem 1 (or its statement) wrong as it induced the reader to think that the conjunction of the 3 properties plays a role in proving the conclusion.

Of course only true theorems may be qualified as wrong.

Taking an absolute stance you may call wrong any theorem that is not a tautology.
A less absolute stance would call wrong any theorem that is not a tautology and in which you forget to mention non-sharpness.

Question 1: is there a better / more adequate term than wrong ( the subtext is: do you think it is a good notion?) .

Question 2: Do you know examples that follow a pattern like B or some variation in lack of tautology?

ADDED TO BE MORE SPECIFIC:

Question 3: More specifically : Are there other types of patterns showing a distance between premise and conclusion. The types need to be common in the mathematical literature, not purely logical types ( of course those are more countable).

$\endgroup$
17
  • 23
    $\begingroup$ -1. There is nothing wrong about writing down a theorem without giving all the possible partial theorems for it (which is impossible, and in quite a few contexts it does not matter at all). And actually nothing to get worried about. $\endgroup$ Commented Oct 5, 2010 at 0:29
  • 5
    $\begingroup$ @Martin: the OP didn't say that he was worried about anything and is using "wrong" in a technical sense here. I do think that the issue of stating theorems which are not sharp -- i.e., not sufficiently revelatory of the true state of affairs -- is interesting (and I agree with you that it is often inevitable). These are issues one confronts when writing up one's results. And, if I am remembering correctly, one of Terry Tao's "advice pieces" on his webpage addresses this issue. $\endgroup$ Commented Oct 5, 2010 at 0:36
  • 6
    $\begingroup$ A subgroup of a subgroup is a subgroup: is that wrong, too? $\endgroup$ Commented Oct 5, 2010 at 2:24
  • 4
    $\begingroup$ Perhaps instead of calling the Theorem of Example B "wrong" one could call it "compound". This neutral word should satisfy those who defend Theorem 1 as being (under appropriate circumstances) the right way to state the result(s), while indicating that it is composed of two or more simpler results. [Not meant very seriously: non-compound theorems could be called "atomic". And since the components don't really interact with each other, maybe "alloyed" is truer to the chemical analogy than "compound".] $\endgroup$ Commented Oct 5, 2010 at 4:17
  • 4
    $\begingroup$ I think equivalence relations are not stable under compositions. One has to take the equivalence relation generated by the composition. (transitivity should fail). $\endgroup$ Commented Oct 8, 2010 at 11:03

4 Answers 4

6
$\begingroup$

A classic example for B is the theorem (proved using Gauss' lemma) usually stated as: if $R$ is a unique factorization domain, then so is the ring of polynomials $R[x]$. Now, $R$ is a UFD iff it is a GCD-domain with no infinite descending chain of proper divisors (ACCP), and

  • if $R$ is a GCD-domain, then so is $R[x]$,

  • if $R$ satisfies ACCP, then so does $R[x]$.

$\endgroup$
1
  • $\begingroup$ You found the best being concrete at that. $\endgroup$ Commented Feb 19, 2011 at 1:12
46
$\begingroup$

I remember years ago sitting in Leo Harrington's office in Berkeley explaining my dissertation to him (he was on my committee), and he spent some time just scanning through the dissertation seeking out any theorem of the form If P, then Q. At such a theorem, he would stop, smile with glee, and then turn to me and ask: Is the converse true? And I would have to explain why or give a counterexample. This little exercise definitely made a better dissertation.

His point, of course, was that such theorems could be seen as flawed in a way very similar to the sense of your question. If the converse was true, then this fact might become part of the theorem, which could be stated as the full if and only if version. And if the converse was not true, then the hypothesis was wastefully strong, and might be improved by weakening it and finding a better theorem. So the exercise guides one to what might be better theorems lurking just nearby your existing results. Since that time, I have often found this perspective illuminating---it has helped my own mathematical writing and understanding in many instances---and so now I find myself carrying out that little exercise with my own students...

At the same time, I recognize that one should not take a dogmatic view on it. There are numerous instances where one wants to draw attention to a surprising or illuminating implication, even though it isn't optimal, because one wants to focus attention on a particular aspect of the mathematics at hand. The choice after all of how to present a mathemetical result is also a choice about non-mathematical issues, such as style or emphasis, and surely many of us have wished in certain cases that the author of a text had given more attention to such presentational aspects of a mathematical text. Perhaps the best way to communicate the mathematical idea you want to communicate is to focus only on the implication P implies Q, even in cases when the hypothesis can be weakened or when the converse is also true, since those other aspects might be a distraction from the construction you want to present or the example you want to explore. Perhaps part of the point is that the implication is easy when P holds, while the optimal implication may be difficult. And so we should relax, and in such circumstances allow such flawed theorems into our papers.

(But still, you should nevertheless try to know the answer to the Harrington exercise for your theorems, even if you decide ultimately not to include those more exact results for the reasons I mentioned.)


But you seemed particularly interested in phenomenon B, so let me offer a specific example, as you requested:

Theorem. Every forcing extension of a model of ZFC is a model of ZFC.

This theorem breaks apart in a manner similar to your equivalence relation example, since for most of the stronger axioms, to verify the axiom in the extension V[G] one appeals to the axiom in the ground model V.

But I definitely don't call this a wrong theorem in any sense, and I wouldn't see it as a necessary improvement to deliniate exactly which ground model axioms are needed to get the particular axioms in the forcing extension, unless the focus of the work was specifically on models that did not satisfy all of ZFC. If one is interested just in ZFC models, then this theorem expresses exactly the desired implication, and the broken-apart version in the style of your Theorem A could be seen as an irrelevant technical distraction.

Almost any theorem about ZFC models would exhibit a very similar phenomenon to this.

$\endgroup$
8
  • 2
    $\begingroup$ A very similar issue arises in reverse mathematics: for most "forward" results we can ask (1) does the reverse implication hold; (2) is the proof uniform; (3) if not, how strong is the uniform version of the principle at hand. In most cases the answers to these are obvious and/or uninteresting, but sometimes they lead to interesting mathematics. $\endgroup$ Commented Oct 5, 2010 at 1:44
  • $\begingroup$ Yes I agree , for A ==> B I view the class you described as " Do we have distance(A,B) =0" . The general question being "How far is A from being a B". The closer the distance: the better, yet under the didactic restriction of having meaningful (interpretable?) entities. I tend to believe that this is not a specifically geometrical point of view but one of the way we learn the world. $\endgroup$ Commented Oct 5, 2010 at 1:46
  • $\begingroup$ @Carl : Can you explained uniform ? An example may do. $\endgroup$ Commented Oct 5, 2010 at 1:47
  • $\begingroup$ @Jérôme: It's an issue that comes up in constructive systems that can be hard to see in classical mathematics. Suppose you prove that for every $A$ there is a $B$ such that some property holds between $A$ and $B$. This is a pure existence statement; you can also ask the stronger question whether $B$ can be obtained in a "uniform" way from $A$. An example: every computable continuous function $f$ on $[0,1]$ with $f(0) < 0 < f(1)$ has a computable root. But there is no effective procedure that can compute a root as a function of the program that computes $f$. $\endgroup$ Commented Oct 5, 2010 at 2:04
  • 2
    $\begingroup$ A vaguely parallel issue in category theory: whether an isomorphism theorem can be strengthened to obtain a natural transformation. $\endgroup$ Commented Oct 5, 2010 at 2:20
10
$\begingroup$

I found the blog piece by Professor Tao that I commented above seems to be relevant to this question:

http://terrytao.wordpress.com/advice-on-writing-papers/dont-overoptimise/

I hope the OP will tell me whether this is, in fact, relevant to the issues he wishes to consider.

If this is on the right track, perhaps "suboptimal", "not sharp" or "unnecessarily weak" give a better description of the phenomenon than "wrong"?

$\endgroup$
4
  • $\begingroup$ But the three terms you propose do not covers the example B of the equivalence relation composition. I browse quickly the text of Tao you mention it make clear and more explicit the case of example A. But does not covers type B. $\endgroup$ Commented Oct 5, 2010 at 1:14
  • $\begingroup$ @JJC: I think I agree with that. I sort of doubt that there is a single general answer to your question, so I addressed the part of it that seemed interesting to me and reminded me of Tao's article. $\endgroup$ Commented Oct 5, 2010 at 2:52
  • 1
    $\begingroup$ Terry Tao's advice speaks against over-generalizing theorems at the cost of a longer proof. I think the OP is talking about generalizing theorems as far as can be done without changing the proof. For example, some theorems about algebras have proofs not requiring associativity; in this case it is not an over-optimization not to require this condition in the theorem itself. (Think of Lie algebras.) $\endgroup$ Commented Oct 5, 2010 at 14:45
  • $\begingroup$ @darij: that may well be; I admit to not totally understanding the OP's question. However, although I grant the distinction you suggest, nevertheless in practice I think it is blurry enough so that what I say seems relevant. In other words, to me a "proof" is not synonymous with any of its incarnations on the page. There are various writeups of various versions of a theorem that your "proof" proves, some of which are longer and harder to write than others. $\endgroup$ Commented Oct 5, 2010 at 20:07
7
$\begingroup$

Another way of understating theorems seems quite common: The theorem merely asserts that two sorts of things are equivalent (or in bijection), for example, equivalence relations on a set and partitions of that set. The proof gives more information, namely the usual ways of transforming any object of either sort into an object of the other sort. That these two transformations are inverse to each other is sometimes not mentioned at all.

There is a conflict here between style and mathematical content. On the one hand, the explicit transformations and the fact that they're inverse to each other are important pieces of information, often needed (though not so often mentioned, since they're so elementary). On the other hand, incorporating them explicitly into the statement of the theorem makes the statement unpleasantly long, and it may obscure the central fact.

When I teach this sort of material, in courses where students are just beginning to do rigorous proofs, I usually first state the mere fact of equivalence, but eventually I write down the whole story (including that the transformations are inverses). And I emphasize that, behind every theorem of the form "these two sorts of things are equivalent," there should ordinarily be a more explicit statement (inverses and all).

$\endgroup$
2
  • 2
    $\begingroup$ @Andreas: Nice class of examples : one point where I half disagree : when you said "unpleasantly long". If the theorem says : "The objects ... called A are in bijection with the objects ... called B. MOREOVER the corespondance can be described as ..." . I believe it is lighter and easy to read if the MOREOVER starts a new line, and you may read the first part only. $\endgroup$ Commented Oct 5, 2010 at 15:10
  • $\begingroup$ Very good response as usual,Andreas.This is really a question of style and for less experienced mathematical students,such purity can be harmfully limiting.Again,repeat my vote to close. $\endgroup$ Commented Oct 9, 2010 at 1:06

Not the answer you're looking for? Browse other questions tagged .