This question has raised from my current research; the terminology and notation comes from either of C. Weibel's "introduction to homological algebra" or "Methods of Homological algebra" by S. Gelfand and Y. Manin. Let $I^\bullet$ be an exact left-bounded complex of modules over a ring $R$ all of whose terms, except for the first leftmost nonzero one, are injective modules. Let $M$ be an $R$-module and take an injective resolution $$0\rightarrow M\rightarrow E^0\rightarrow E^1\rightarrow\cdots$$ of $M$; this can be described in terms of a quasi isomorphism $M\rightarrow E^\bullet$ where I view $M$ as a complex concentrated in degree zero and $E^\bullet$ is just the deleted resolution $0\rightarrow E^0\rightarrow E^1\rightarrow\cdots$. My question is that does the functor $Hom_R^\bullet(I^\bullet, -)$, as defined in the aforementioned books, preserve this quasi isomorphism? That is to say, I want to know if the complexes $Hom_R^\bullet(I^\bullet, M)$ and $Hom_R^\bullet(I^\bullet, E^\bullet)$ are quasi isomorphic.

My plan is to use Acyclicity Theorem, mentioned on page 54 of B. Iversen's "Cohomology of sheaves". For, I need to show that both $M$ and $E^\bullet$ are $Hom_R^\bullet(I, -)$-acyclic in the sense that for $i\geq 1$, the $i$-th right derived functor ${\mathbb R}^i Hom_R(I^\bullet,-)$ vanishes both over $M$ and $E^\bullet$. It seems to me that this holds because $I^\bullet$ is exact and $E^\bullet$ is left-bounded. Am I true? Any comment is appreciated.