Do all spaces doubly covered by $S^{2n}$ have the homeomorphism type of $\mathbb{P}^{2n}_{\mathbb{R}}$? For reference, my motivation: It's of interest to classify free actions of groups on spheres of positive even dimension. Establishing such a classification up to homotopy is not too difficult: Every free group action on a sphere of even dimension is homotopic to either the trivial action by the trivial group or the antipodal action by $\mathbb{Z}/2$. The question in the title is, by the reduction that follows, equivalent to whether this classification is conserved if the "homotopic" in the above sentence is strengthened to "homeomorphic".
Suppose that every space doubly covered by $S^{2n}$ has the homeomorphism type of $\mathbb{P}^{2n}_{\mathbb{R}}$ and let $\tau\ \colon S^{2n}\to S^{2n}$ be some continuous involution lacking fixed points. Then:

*

*By the compactness of $S^{2n}$, $$x\mapsto\text{dist}_{\text{standard subspace Euclidean metric on }S^{2n}}\left(x,\tau\left(x\right)\right)\colon S^{2n}\to\mathbb{R}_{\geq 0}$$ attains a nonzero mminimum on its domain.


*By (1), the projection map $$\gamma\ \colon S^{2n}\to\text{coeq}\left(S^{2n}\substack{\overset{\text{id}}{\longrightarrow}\\ \underset{\tau}{\longrightarrow}}S^{2n}\right)$$ is a covering map.


*By (2), there exists an isomorphism $$\psi\ \colon \text{coeq}\left(S^{2n}\substack{\overset{\text{id}}{\longrightarrow}\\ \underset{\tau}{\longrightarrow}}S^{2n}\right)\to\mathbb{P}_{\mathbb{R}}^{2n}.$$


*By (2) and the lifting theorem for covering spaces, the $\psi$ of (3) lifts to an isomorphism $$\tilde{\psi}\ \colon S^{2n}\to S^{2n}$$ such that $$\text{anti}\circ\tau = \tau\circ \tilde{\psi}$$ (with $\text{anti}\ \colon S^{2n}\to S^{2n}$ the antipodal involution), precisely the desideratum.
 A: One approach to a homeomorphism classification of closed manifolds simply homotopy equivalent to a closed manifold $X$ of dimension $>4$ is to compute the topological structure set $\mathcal S^s_\text{TOP}(X)$ and the group of homotopy classes of simple homotopy equivalences $\text{Aut}_s(X)$. Then $\text{Aut}_s(X)$ acts on $\mathcal S^s_\text{TOP}(X)$ by composition and the quotient is the desired set of homeomorphism classes of closed manifolds simply homotopy equivalent to $X$.
For $X=\mathbb RP^n$ the topological structure set is known, and the structure set always has at least 4 elements, and it is finite unless $n-3$ is divisible by $4$.
The group $\text{Aut}_s(\mathbb RP^n)$ is trivial if $n$ is even and has order $2$ if $n$ is odd. See  Corollary 6 in "Coverings of fibrations" by Becker and Gottlieb.
Thus there are lots of fake even-dimensional real projective spaces in  dimensions $>4$.
By Freedman's work this can be extended to dimension $4$, see   Invariant knots of free involutions on $S^4$ by Ruberman for examples of fake $\mathbb RP^4$.
