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Say that a tile $T$ that alone can tile the plane—a monohedral tile—is rigid if it is not the case that $T$ can be slightly deformed to $T'$ so that:

  • $T'$ can also tile the plane
  • $T'$ is arbitrarily close to $T$, say, according to Hausdorff distance.
  • The tiling by $T'$ is "combinatorially equivalent."

For example, the familiar regular hexagon tiling is not rigid, because it can be "compressed" vertically:


     SquashedHex

Rigid tilers are "brittle" in that even a slight deformation changes their tiling properties. Since all triangles and all quadrilaterals are monohedral tilers, it is not difficult to claim that no $n\in\{3,4\}$-sided polygons are rigid tilers.

Questions:

Clearly the pentagonal cmm (2*22) tiler is not rigid, because the pentagon tile is simply a hexagon split vertically:

cmm (2*22)
   Wikipedia image

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