9
$\begingroup$

$\DeclareMathOperator\SL{SL}$I would like to know if there is a full list of isomorphic class of finite subgroups of $\SL_5(\mathbb{C})$. I have already found the classification for $\SL_2$ and $\SL_3$. Thank you very much!

$\endgroup$
9
  • 2
    $\begingroup$ Incidentally, what is the classification for SL3? I only know the SL2 case. $\endgroup$ Jul 23, 2021 at 14:59
  • 5
    $\begingroup$ @TheoJohnson-Freyd: See H.F. Blichfeldt, The finite, discontinuous, primitive groups of collineations in three variables. Math. Ann. 63 (1907), no. 4, 552–572. $\endgroup$ Jul 23, 2021 at 16:02
  • 1
    $\begingroup$ I think the original result for SL3 is due to Camille Jordan digizeitschriften.de/dms/img/?PID=GDZPPN00215675X $\endgroup$ Jul 23, 2021 at 18:15
  • 2
    $\begingroup$ @AbdelmalekAbdesselam: Blichfeldt credits Jordan but points out that Jordan missed two perfect subgroups of $SL_3(C)$, namely $GL_3(2)$ and $3A_6$, of orders $168$ and $1080$. $\endgroup$ Jul 23, 2021 at 23:34
  • 1
    $\begingroup$ Since you did not restrict to irreducible groups, you also need the list of irreducible finite subgroups of ${\rm GL}(4, \mathbb{C})$ in addition to the groups given in Richard's answer. These groups were also know to Blichfeldt (at least the primitive ones). There were some omissions/errors, eg one found by Conway. $\endgroup$ Jul 24, 2021 at 15:43

1 Answer 1

13
$\begingroup$

The irreducible primitive finite subgroups of $SL_5(C)$ were classified up to isomorphism by Richard Brauer: "Über endliche lineare Gruppen von Primzahlgrad", Math. Ann. 169 (1967), 73–96.

$\endgroup$
3
  • 4
    $\begingroup$ By the way, believe that some of the groups in Brauer's list are actually imprimitive : for example, the $5$ dimensional character of $A_{5}$ is induced from any non-trivial linear character of $A_{4}.$ $\endgroup$ Jul 23, 2021 at 16:02
  • 3
    $\begingroup$ @GeoffRobinson That is a slightly unusual example of an imprimitive group in that it acts faithfully on the blocks, so its kernel is trivial. $\endgroup$
    – Derek Holt
    Jul 23, 2021 at 16:25
  • 2
    $\begingroup$ @GeoffRobinson: Thanks for the clarification. $\endgroup$ Jul 23, 2021 at 23:39

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.