On page 87 of the book Hyperbolic Conservation Laws in Continuum Physics by C. M. Dafermos, there is a theorem which I summarise as follows
Theorem. (Theorem 4.5.2 in the book.) Let $U$ be a weak solution to the conservation law $\partial_t U + \text{div }G(U) =0,$ with initial data $U_0$ and $U\in\mathcal O\subseteq \mathbb R^n, x\in \mathbb R^m, G$ an appropriate matrix-valued function. Suppose that $U_0 - \bar U \in L^2$ for some constant $\bar U,$ and $\bar U$ satisfy the entropy condition for entropy $\eta.$ If we normalise $\eta$ so that $\eta(\bar U ) =0, D\eta(\bar U) =0,$ then $$S(t) = \int_{\mathbb R^m} \eta (U(x,t)) dx$$ is a decreasing function of $t.$
I am worried about the statement of this theorem because the only assumption made on $G$ is that it is smooth in the image of $U.$ (This is stated at the beginning of the chapter.) No other technical assumptions are given. This seems insufficient to control the growth of $Q,$ and there are problems that integrals of $Q$ diverging.
If we look into the proof, there is a sentence: "fix $s$ sufficiently large so that $s\eta \geq |Q|$ for all output of the function $U.$" I do not know why such $s$ must exist. We know that $DQ_\alpha = D\eta \cdot DG_\alpha,$ by the definition of entropy flux. So if $G_\alpha$ grow very fast, we cannot expect $Q$ to be dominated by $\eta.$ Apparently some bound on $G$ need to be assumed; but nearly nothing is assumed in the book. (Of course we can normalise so that $Q(\bar U) =0$. But if we do so, there is no guarantee that $U$ will always stay close to $0$ at infinity.)
So, are we implicitly assuming some conditions on $G$, which are not stated in the book?