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Q: What number is less than 30 leaves a remainder of 3 when divided by 5 and a remainder of 2 when divided my 3?

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3 divided by 2 has a remainder of 1. Which is 1 less than 2.

56

24 is answer.

1098765433 will have a remainder of 1.

The remainder is always 31 or less.

37 is the number.

Every 2 digit number, when divided by the number one less than it, will result in a remainder of 1.

No answer is possible as any number divided by 9 must either be exactly divisible by 9 or leave a remainder less than 9.

14. The largest possible number for a remainder is 1 less than the divisor.

12.5

29

Yes- A remainder can be any number less than the dividend (the number by which the divisor is divided). An example of a 2 digit number is: 131/11=11 remainder 10.

The largest possible number for a remainder is 1 less than the number of the divisor, so it is 5.

989. If there is a remainder of 2 when divided by 3, the number is one less than a multiple of 3. If there is a remainder of 4 when divided by 5, the number is one less than a multiple of 5. Thus the number required is one less than a multiple of the lowest common multiple of 3 and 5 (that is 15). So what is needed is an even multiple of 15 less than or equal to 1000: 1000 ÷ 15 = 662/3 Thus the highest even multiple of 15 not greater than 1000 is 66 x 15 = 990, and the required number is 989.

LCM(2, 3, 4, 5, 6, 10) = 60 so the number is 61.

Nothing. The remainder has to be less than the divisor.

The numbers that divide evenly by 7 and less than 75 are 7, 14, 21, 28, 35, 42, 49, 56, 63, and 70 Of the above numbers 56 when divided by 11 gives a quotient of 5 and a remainder of 1 Hence the number is 56

The valid factors of 76 are: 2,4,19,38 We are looking for a factor that leaves a remainder of 3 when divided by four. Since this implies that it is odd, it must be 19.

I would think 100 is the answer.

That's not possible. The largest single-digit number by which you might divide is 9. And, by definition, the remainder is always LESS than the number by which you divide. Thus, the largest remainder you can get, when you divide by 9, is 8.

0.0385

Any non-negative number less than 8. If the number being divided is not a whole number, the remainder will not be a whole number either.

23 / 7 = 3 R 2, 23 < 40, 23 / 4 = 5 R 3

This is almost equivalent to asking for the factors of 2000: If 2000 is divisible (for example) by 100, 2006 divided by 100 leaves a remainder of 6. However, you have to exclude numbers less than or equal to 6; for example, if you divide 2006 by 5, you get a remainder of 1, not 6. So, just find all the factors for 2000, then exclude those that are less than or equal to 6.This is almost equivalent to asking for the factors of 2000: If 2000 is divisible (for example) by 100, 2006 divided by 100 leaves a remainder of 6. However, you have to exclude numbers less than or equal to 6; for example, if you divide 2006 by 5, you get a remainder of 1, not 6. So, just find all the factors for 2000, then exclude those that are less than or equal to 6.This is almost equivalent to asking for the factors of 2000: If 2000 is divisible (for example) by 100, 2006 divided by 100 leaves a remainder of 6. However, you have to exclude numbers less than or equal to 6; for example, if you divide 2006 by 5, you get a remainder of 1, not 6. So, just find all the factors for 2000, then exclude those that are less than or equal to 6.This is almost equivalent to asking for the factors of 2000: If 2000 is divisible (for example) by 100, 2006 divided by 100 leaves a remainder of 6. However, you have to exclude numbers less than or equal to 6; for example, if you divide 2006 by 5, you get a remainder of 1, not 6. So, just find all the factors for 2000, then exclude those that are less than or equal to 6.

That number would be 43.