- Thread starter
- #1

- Feb 5, 2012

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Recently I encountered the following problem. Hope you can confirm whether my method is correct. My answer seems so trivial and I have doubts whether it is correct.

**Problem:**

Find the Jordan normal form of a unitary linear transformation.

**My Solution:**

Now if we take the matrix of a unitary linear transformation (say \(A\)) it could be diagonalized; \(A=VDV^*\), where \(D\) is a diagonal unitary matrix and \(V\) is a unitary matrix. So therefore the Jordan normal form is obviously \(D\), where the diagonal elements consist of the eigenvalues of \(A\).