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Let $X$ be an algebraic stack and let $f: S \to X$ be a smooth covering of $X$ by a scheme $S$.

Motivation: Forgetting about stacks for a moment and going back to covering spaces: Given a covering map $f: Z \to Y$, with $Z$ connected and $Y$ locally connected, then $\operatorname{Aut}(Z/Y)$ acts properly and discontinuously on $Z$. Moreover, if $\operatorname{Aut}(Z/Y)$ acts transitively on a fiber of $p \in Y$, then the covering is a $G=\operatorname{Aut}(Z/Y)$-covering in the sense that $f: Z \to Y \cong Z/\operatorname{Aut}(Z/Y)$ is a quotient map.

I am interested in making an analogous statement in the case of a smooth cover $f:S \to X$ of an algebraic stack $X$. (Of course, dropping words like properly and discontinuously and keeping in mind that $f$ is not finite 'etale and thus not a covering map in the above sense).

In particular, I want to describe $\operatorname{Aut}(S/X)$. The "elements" of $\operatorname{Aut}(S/X)$ are maps $\phi: S \to S$ such that $f \circ \phi =f$. On the other hand, $f: S \to X$ can be identified with a unique object $s \in X(S)$ (up to $2$-isomorphism?) by the 2-Yoneda lemma and so it seems like $\operatorname{Aut}(S/X)$ should have an interpretation in terms of the groupoid of maps $s \to s$ lying over a given $\phi: S \to S$.

That is all very abstract, so let us just suppose that the elements of $X(S)$ have some geometric interpretation, for example, the object $s \in X(S)$ is a family of genus g curves $C$ over a scheme $S$.

(1). Is there an interpretation of the groupoid $s \to s$ lying over $\phi: S \to S$ in terms of a group automorphisms of $C$ over $S$?

(2). Moreover, how would this group act on a "fiber" $S \times_{X,g} T$ (a sheaf on the category $Sch/S \times T$?) over $g: T \to X$?

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    $\begingroup$ (1) One simple example of a stack is a quotient stack $X = [S/G]$. In this case, the automorphisms of $S$ over $X$ will include, at least, the element of $G$, and will be exactly the elements of $G$ if $S$ is connected. So any finite group action of $G$ on $X$ can potentially appear. (2) If $S$ is a moduli space of geometric objects like curves, automorphisms will match exactly the notion of automorphisms of a family: a map $C \to C$ and a map $S \to S$ forming a commutative square with $C \to S$. $\endgroup$
    – Will Sawin
    Commented Apr 16, 2021 at 18:55
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    $\begingroup$ The objects of $\text{Aut}(S/X)$ are not just maps $\phi:S\to S$ such that $f\circ \phi=f$, they are pairs $(\phi,u)$ composed of a map $\phi:S\to S$ and an isomorphism $u:f\circ \phi \to f$. $\endgroup$ Commented Apr 16, 2021 at 19:14
  • $\begingroup$ Is it possible to identify Aut(S/X) with Aut(C,S) by a Yoneda-typer argument? $\endgroup$
    – user
    Commented Apr 16, 2021 at 22:36

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