Let $X$ be a (non-empty) compact subset of $D(0,M):=\left\{x\in \mathbb{R}^n:\, \|x\|\leq M\right\}$, and let $f:X\rightarrow Y$ be uniformly continuous; for some metric space $Y$. Are there any known result guaranteeing that $f$ can be extended to a uniformly continuous function $F:D(0,M)\rightarrow Y$ such that the modulus of continuity of $f$ is (point-wise) greater-than or equal to the modulus of continuity of $F$?

  • $\begingroup$ If $X$ is the sphere, then possibility of extension means that $n-1$-th homotopy group of $Y$ vanish. Also, it doesn't say in the body of the question that modulus of continuity has to be preserved (as you mentioned in the title). Could you please clarify? $\endgroup$
    – erz
    Mar 15, 2021 at 6:12
  • $\begingroup$ I added the requested clarification. However, I don't see the homotopic argument. $\endgroup$ Mar 15, 2021 at 10:23
  • $\begingroup$ one of the definition of having vanishing $n-1$-th homotopy group is precisely existence of extension of any continuous map $f:S^{n-1}\to Y$ to $F:D_{n}\to Y$ $\endgroup$
    – erz
    Mar 15, 2021 at 16:47
  • 1
    $\begingroup$ See for example Hatcher - Algebraic topology, chapter on homotopy groups $\endgroup$
    – erz
    Mar 16, 2021 at 17:42
  • 1
    $\begingroup$ I did not claim it does. It's just a necessary condition $\endgroup$
    – erz
    Mar 19, 2021 at 18:11


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.