2
$\begingroup$

I am studying derived quot schemes in the paper Ciocan-Fontanine and Kapranov, “Derived Quot schemes” .

On page 36 ~ 37, the derived linearity locus is defined.

Let $S$ be a $\mathbb{Z}_-$-graded dg-scheme, $A$ a $\mathbb{Z}_-$-graded and $M, N$ two quasi-coherent dg-sheaves on $S$. Suppose $M, N$ are locally free and dg-modules over $A \otimes_\mathbb{K} \mathcal{O}_S$ and we have a morphism $f:M \rightarrow N $ of $\mathcal{O}_S$-dg-modules. Then, the derived linearity locus $RLin_A(f)$ is defined to be the fiber product $|R\mathcal{Hom}_{A \otimes \mathcal{O}_S}(M,N)| \times_{|\mathcal{Hom}_{\mathcal{O}_S}(M, N)|} S$.

And, according to Proposition 3.8.4, $RLin_A(f)$ is obtained as $ Cone\{\mathcal{O}_S \overset{\delta f}{\rightarrow} \mathcal{Hom}_{\mathcal{O}_S} (Bar_A(M), N) \}[1] $

, where $Bar_A(M)$ is the Bar resolution of $A$-module $M$ and $\delta f \in \mathcal{Hom}_{\mathcal{O}_S}(A \otimes M , N)$ takes $a \otimes m \mapsto f(a \otimes m) - a f(m)$.

However, I can't understand what this is as a dg-scheme and why this is correct.

I'd be grateful if you could tell me these. Thank you !

$\endgroup$
2
  • 3
    $\begingroup$ Your tensor product in the definition of the fibre product should just be $\times$, as these are dg schemes, not cdgas. The expression in Prop 3.8.4 is probably intended to be read as taking Spec Symm of the dual. $\endgroup$ Feb 27, 2021 at 10:30
  • $\begingroup$ Thank you for pointing it out. \otimes shoud be \times. It is exactly as you said about the expression in Prop 3.8.4. However, this complex seems to have a non-zero term in negative degree. $\endgroup$ Feb 27, 2021 at 13:41

1 Answer 1

2
$\begingroup$

Your tensor product in the definition of the fibre product should just be ×, as these are dg schemes, not cdgas. The expression in Prop 3.8.4 is probably intended to be read as taking Spec Symm of the dual.

So I think they've just put the wrong shift in: take -1 instead.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.