2
$\begingroup$

Let $A$ be an infinite non-negative matrix with integer entries ($a_{ij} \geq 0, \forall i,j \in \mathbb N$). Suppose that $A$ is irreducible, aperiodic, and recurrent. So that it satisfies the condition of the generalized Perron-Frobenius theorem. In particular, there exists a Perron eigenvalue $\lambda >0$ (assumed to be finite) and a strictly positive eigenvector $x = (x_i)$ such that $Ax =\lambda x$.

My question: under what conditions on $A$ can one find a probability eigenvector $x$, i.e., $\sum_i x_i =1$?

I hope that this question has been discussed in the literature, and any references or suggestions are greatly appreciated.

Remark There is an obvious condition: $A$ is positive recurrent and has the equal column sum property $\sum_j a_{ij} = c, \forall i$. But this condition seems too strong.

Remark I missed to mention an important property of $A$: for all $n$, the entries $a^{(n)}_{ij}$ of $A^n$ are finite. It happens, for example, when every column of $A$ contains only finitely many nonzero entries.

$\endgroup$
5
  • 1
    $\begingroup$ I have difficulties to follow the question. Could you please clarify the following points? (i) What does aperiodic and recurrent mean for an infinite matrix? In my experience, those notions are typically defined for Markov chains, but not for general infinite matrices. (ii) Which result precisely do you refer to as "the generalized Perron-Frobenius theorem"? There are many infinite-dimensional Perron-Frobenius type results, but all those that I have seen so far are about linear operators on certain classes of Banach spaces, not about infinite matrices. $\endgroup$ Commented Jan 30, 2021 at 3:38
  • $\begingroup$ (iii) Do I understand correctly that your question is actually whether $x$ can be chosen to be in $\ell^1$? $\endgroup$ Commented Jan 30, 2021 at 3:38
  • $\begingroup$ There is a long list of references about the Perron-Frobenius theorem for infinite matrices. I use the (standard) terminology from Chapter 7 of the book "Symbolic dynamics" by B. Kitchens. This terminology is similar to that used in Markov chains. $\endgroup$
    – SIB
    Commented Jan 30, 2021 at 4:25
  • $\begingroup$ Yes, it is an equivalent formulation of the question saying that $x \in \ell^1$. $\endgroup$
    – SIB
    Commented Jan 30, 2021 at 4:27
  • 1
    $\begingroup$ Thank you for your response and for the reference! I found the reference quite interesting, since I never looked at Perron-Frobenius theory from this perspective. (For people who are not familiar with the framework of infinite matrices - like me, for instance -, it might still be worthwhile, though, to note explicitly that Kitchens actually says in Remark 7.1.2 that his terminology is "slightly nonstandard", and that, for instance, his usage of "transient" and "recurrent" is not consistent with the usage of these notions in probability theory, in general.) $\endgroup$ Commented Jan 30, 2021 at 15:59

0

You must log in to answer this question.

Browse other questions tagged .