# find a parametric equation for the that is perpendicular to the graph of the given equation at the given point: z=x3-xy2 , (-1,1,0) [closed]

i am still a beginner in this and don't know how to do it so please can you help? find a parametric equation for the line that is perpendicular to the graph of the given equation at the given point:

z=x^3-xy^2 , (-1,1,0)

New contributor
jeff is a new contributor to this site. Take care in asking for clarification, commenting, and answering. Check out our Code of Conduct.
• Any normal to a surface given by an implicit equation $f(x,y,z)=0$ in a point $M_0(x_0,y_0,z_0)$ is directed by the gradient $G_0(\partial f/\partial x, \partial f/\partial y,\partial f/\partial z)$ computed in $M_0$ (please note the precise words). Parametric equations are given by $(x,y,z)=M_0+t G_0$. – Jean Marie Becker yesterday
• Welcome to Mathoverflow. I hope the excellent comment by @JeanMarieBecker helps you with your question. You're unlikely to receive more detailed answers, since a question of the type you're asking isn't really in the right place here - Mathoverflow is for research-level questions. A better place for this kind of question is math.stackexchange.com . – Michael Engelhardt yesterday