Yes, this is called the Phragmen-Lindelof Principle: For every region on the Riemann sphere, if $h$ is subharmonic and bounded from above, and
$$\limsup_{z\to\zeta}h(z)\leq 0$$ for all $\zeta\in\partial\Omega$, except finitely
many points, then $h\leq 0$ in $\Omega$. If your domain $\Omega$ is an unbounded domain in $C$, just include $\infty$ to this finite exceptional set.

There are many improvements of this, for example, finite exceptional set can be replaced by a set of zero capacity. Boundedness from above can be replaced by a weaker condition $h(z)<o(\log|z|),\; z\to\infty$. This can be replaced by a
weaker growth condition,
if something is known about the shape of the unbounded domain near infinity. For example, if the portion of $\Omega$ near $\infty$ is contained in a sector of opening $<\pi/\alpha$, then instead of boundedness one can impose the growth condition $h(z)<o(|z|^\alpha)$.

Refs. Ransford, Potential theory in the plane,

Levin, Lectures on entire functions,

Hayman, Kennedy, Subharmonic functions.

In fact, the proof is very simple. Suppose $h$ is bounded from above and $h(z)\leq 0$ on $\partial\Omega$, where $\Omega$ is an unbounded domain.
Here $\partial$ is with respect to $C$, so it does not include $\infty$.
Suppose for simplicity that $\Omega$ does not intersect the unit disk. Consider $u(z)=h(z)-\epsilon\log|z|$, where $\epsilon>0$. Then $\limsup_{z\to\zeta}u(z)\leq 0$ for $\zeta\in \partial^*\Omega$, the boundary with respect to the Riemann sphere, so it includes $\infty$. By the usual Maximum principle we conclude that $u(z)\leq 0$ on $\Omega$.
Passing to the limit for fixed $z$ as $\epsilon\to 0$, we obtain $h(z)\leq 0$.

To obtain the result under other conditions, you use other auxilliary functions in place of $\log|z|$.