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I consider the curve $c(t)=(x(t),y(t))$ in $\mathbb{R}^2$ such that

$\frac{d^2x(t)}{dt^2}=-(a\sin t+b)\frac{dy(t)}{dt}$

$\frac{d^2y(t)}{dt^2}=(a\sin t+b)\frac{dx(t)}{dt}$

$a,b\in\mathbb{R}$

Is the orbit curve of solution of above equations known?

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    $\begingroup$ What initial conditions? For example, all lines are solutions. $\endgroup$
    – LSpice
    Commented Aug 5, 2020 at 15:44

1 Answer 1

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It is not clear what you mean by "known" but this system can be solved explicitly, in quadratures of elementary functions. Set $x'=u,\; y'=v,\; g(t)=a\sin t+b$. Then your system becomes $$u'=-gv,\quad v'=gu.$$ Multiplying the first equation on $u$ and second on $v$ and adding, we obtain $u'u+v'v=0,$ therefore $u^2+v^2=c$. Then the first equation becomes $(u')^2=g^2(c-u^2)$, and this is a separable equation, with an explicit integral.

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  • $\begingroup$ Thanks for your answer. Excuse me for the wide implications of my remarks. I wanted to know if it had a name or if there was a reference to be cited. $\endgroup$
    – Matsuno
    Commented Aug 5, 2020 at 17:25
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    $\begingroup$ If this system is interesting for some reasons, perhaps it has a name, but you know better where it comes from. $\endgroup$ Commented Aug 6, 2020 at 1:23

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