Imagine we have a sequence of finite measures $\nu_n << \mu_n$ (on the torus $\mathbb{T}^2\subseteq \mathbb{R}^2$) converging weakly to some measures $\nu << \mu$. Do we automatically have that the Radon-Nikodým derivatives $h_n$ of $\nu_n$ wrt. $\mu_n$ converge to the Radon-Nikodým derivative $h$ of $\nu$ wrt. $\mu$?
Does the situation becomes easier if we assume that $0\leq h_n \leq 1$ and $0\leq h\leq 1$?
Does the results carry over if we consider finite random measures instead of deterministic measures? And is the result still available if the convergence is only in the distributional sense, i.e. for compactly supported smooth functions?
Thanks a lot for your help!