Suppose $\mathfrak{g}$ is a real Lie algebra integrating to the connected Lie group $G$. One may consider the $G$equivariant cohomology of $\mathfrak{g}$ ($\mathfrak{g}^*$) where the $G$action is the adjoint (coadjoint) representation. That is, the cohomology induced by the cochain complex of $G$invariant differential forms on $\mathfrak{g}$. (Or, more generally, $G$invariant $V$valued forms where $V$ is the target of a linear representation of $G$). When $G$ is compact, it follows from a theorem of Chevalley and Eilenberg that this cohomology vanishes in all degrees. I am however interested in the semisimple case. What is known in general about this cohomology and its vanishing? What is known for specific semisimple Lie algebras? Can this cohomology be tied to the standard Lie algebra cohomology?

$\begingroup$ Whitehead‘s Lemmas answer this at least in degree 1 and 2: en.wikipedia.org/wiki/Whitehead%27s_lemma_(Lie_algebra) $\endgroup$ – ThiKu Jul 5 at 12:10
It vanishes as well. The complex of differential forms on $\mathfrak{g}$ is null homotopic through the standard nullhomotopy coming from the linear homotopy to the origin. Since the $G$action preserve this nullhomotopy, it is $G$equivariantly null and so its $G$invariants subcomplex is null as well.

$\begingroup$ Could you please also explain where is semisimplicity used? $\endgroup$ – მამუკა ჯიბლაძე Jul 5 at 11:55

$\begingroup$ it is not used anywhere. Its just the fact that as a $G$space the representation is a contractible space. $\endgroup$ – S. carmeli Jul 5 at 12:02

$\begingroup$ So it is also true when $G$ is, say, solvable?? $\endgroup$ – მამუკა ჯიბლაძე Jul 5 at 12:10

$\begingroup$ I might be confusing with something else of course, but it seem unconditional to me, its just a contractible complex. Maybe you have another complex then I in mind? $\endgroup$ – S. carmeli Jul 5 at 12:18

$\begingroup$ Please get me right  I am not sceptical, I am surprised :) $\endgroup$ – მამუკა ჯიბლაძე Jul 5 at 12:22