3
$\begingroup$

In Demazure's Lectures on p-Divisible Groups, an affine formal scheme over a field $k$ is defined as $\mathop{\mathrm{Spf}}(A)$ for some profinite $k$-algebra $A$. However, in EGA I Chap. 10, an affine formal scheme is defined as $\mathop{\mathrm{Spf}}(A)$ for some admissible ring $A$. My question is: Is Demazure's definition a special case of EGA's definition? If not, is there a more general definition which contains both of them as special cases.

$\endgroup$
4
  • $\begingroup$ Your question is not about formal shemes, but about if a profinite $k$-algebra, for $k$ a field, is an admissible (topological) ring (with the topology given by being profinite). And the answer is clearly affirmative. So Demazure's definition can be seen as a special case of EGA's definition. $\endgroup$ Commented Jun 13, 2020 at 8:52
  • $\begingroup$ @Nulhomologous But it seems that an infinite product of $k$ is a profinite $k$-algebra which is not admissible. $\endgroup$ Commented Jun 13, 2020 at 9:29
  • $\begingroup$ I don't see how an infinite product of k could be a profinite k-algebra. $\endgroup$ Commented Jun 13, 2020 at 19:42
  • $\begingroup$ @Nulhomologous According to Demazure, a profinite $k$-algebra is equivalent to a left exact functor from the cat $\mathcal C$ of finite $k$-algebras to the cat of sets. Let $I$ be any set. Then the constant sheaf on $\mathcal C$ with value in $I$ (i.e. $R \mapsto$ locally constant function from $\mathop{\mathrm{Spec}}(R)$ to $I$) corresponds to the product of copies $k_i$ of $k$ indexed by $I$. In particular, the constant $p$-divisible group $\mathbb Q_p/\mathbb Z_p$ over $k$ should corresponds to an infinite product of $k$. $\endgroup$ Commented Jun 14, 2020 at 1:49

0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Browse other questions tagged or ask your own question.