Global splitting field for algebras Let $A$ be a finite dimensional algebra.
A field $K$ is a splitting field for an indecomposable $A$-module $M$ in case the local algebra $End_A(M)/(rad(End_A(M))$ is 1-dimensional.
$K$ is called a global splitting field for an algebra $A$ in case every indecomposable $A$-module splits.

Question: Is there a concrete example of a representation-infinite algebra $A$ over a finite field that is a global splitting field for $A$?

Answer by Jeremy Rickard: No.
This motivates the follow up question:

Question: Is a field $k$ algebraically closed if and only if it is the global splitting field of a representation-infinite $k$-algebra $A$?

 A: Let $k$ be a finite field and $A$ a representation-infinite finite dimensional $k$ algebra. By the second Brauer-Thrall conjecture, $\bar{k}\otimes_kA$ has infinitely many nonisomorphic indecomposable modules of some dimension, and so has some that are not defined over $k$ (i.e., not of the form $\bar{k}\otimes_kM$ for any $A$-module $M$). However, such a module is defined over some finite field extension of $k$: namely, the extension generated by its structure constants.
So we have a finite extension $K$ of $k$, and an indecomposable $K\otimes_kA$-module $N$ that is not of the form $K\otimes_kM$ for any $A$-module $M$.
Let $X$ be any indecomposable direct summand of the restriction $\text{Res}^{K\otimes_kA}_A(N)$.
Since $K\otimes_k\text{Res}^{K\otimes_kA}_A(N)$ is the direct sum of $|K:k|$ Galois conjugates of $N$, $K\otimes_kX$ is the direct sum of some of the Galois conjugates of $N$, and more than one, since $N$ is not defined over $k$.
Hence (using the fact that $K$ is a separable extension of $k$, so that extending scalars to $K$ commutes with taking radicals of algebras)
$$\dim_k\text{End}_A(X)/\text{rad}(\text{End}_A(X))
=\dim_K\text{End}_{K\otimes_kA}(K\otimes_kX)/\text{rad}(\text{End}_{K\otimes_kA}(K\otimes_kX))$$
is greater than $1$.
