An interesting combinatorial identity is the Vandermonde convolution identity:
$$ \sum_k {n\choose k}{m\choose s-k} = {n+m \choose s},$$
which can be proved by considering the coefficients in $(x+1)^{n+m} = (x+1)^n (x+1)^m$. I am interested in the behavior of the summands: which summands among them contribute the most?.
More specifically, I'd like to look at the behavior of the function
$$ F(k) = \frac{{n\choose k}{m\choose s-k}}{{n+m \choose s}}. $$
In a specific probabilistic problem, intuition suggests that $F(k)$ peaks near $k$, with $\frac{n}{n+m} = \frac{k}{s}$. Indeed, in the limit case $s = n+m$, $k$ had better be $n$ for the value to survive. However, I'm not satisfied with the limit case.
Given that $F$ does peak around $k = k^* := \frac{ns}{n+m}$, I want to know how much it peaks. Thus the following question:
Find the smallest possible non-negative integer $\epsilon$ such that
$$ \sum_{k \in [k^*-\epsilon, k^*+\epsilon]} F(k) > 90\%.$$
The answer $\epsilon$ depends on $n, m, s$, and "$90\%$".