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(Question is short and straight-forward. )

What is/are "nice and non-trivial" series representation/s of $\log(|\zeta(\frac{1}{2}+it)|)$ ??

By "nice and non-trivial" I mean contains no more than double sum and no direct Taylor expansion

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    $\begingroup$ Something tells me that you want to use it for "Balazard, Saias, and Yor's equivalence to the Riemann Hypothesis" $\endgroup$
    – user145059
    Commented Apr 9, 2020 at 10:34

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Hint: you might start with wely Bound which is defined as :$t\in\mathbb{R}$, then $|\zeta(\frac{1}{2}+it)|\leq c(|t|+1)^{1/6}$ this means that $\log|\zeta(\frac{1}{2}+it)|\leq \frac16 \log(c|t|+1)$, you can easly deduce the representation series of $\log(c|t|+1)$ which it is defined as : $\log(c|t|+1)=\log(c|t|)-\sum_{k=1}^{\infty} \frac{(-1^k)}{k c^k|t|^k},|ct|>1$,And if you want really to find such non trivial series representation of $\zeta(0.5+i t)$ in general , you may look to find such polynomial of degree N using local trigonometric approximation I recomond you to check this nice post by Terence Tao

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  • $\begingroup$ This is awesome! Can you give a source for that first bound, though? And can you explain what is $c$ in that bound? $\endgroup$
    – DUO Labs
    Commented May 5, 2020 at 2:52

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