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This question is largely connected to the question presented here.

Let $T$ be the theory extending first order logic with equality, with primitives of a binary symbol $\in$, an unary symbol $S$; and the following axioms:

Axiom of extension: \begin{equation} \forall x \forall y (\forall z (z \in x \leftrightarrow z \in y) \rightarrow x = y) \end{equation}

Axiom of heredity:\begin{equation} \forall x \forall y (S x \land (y \in x \lor y \subset x) \to S y) \end{equation}

Axiom schema of reflection:\begin{equation} S p_1,...,S p_n \to \\ \forall y (\phi y \rightarrow S y) \rightarrow \exists x: S x \land \forall y (y \in x \leftrightarrow \phi y) \end{equation} for every formula $\phi$ not containing $S$ nor $``x"$, whose parameters are among $p_1,..,p_n$ symbols.

Axiom of $\neg S$-separation: \begin{equation} \forall a \exists x \forall y (y \in x \leftrightarrow y \in a \land \neg Sy) \end{equation}

This theory is a proper fragment of Muller's class theory. It can prove axioms of: empty set, pairing, set union, power, separation, and infinity over objects fulfilling $S$. It is stronger than Zermelo since it can prove the existence of $\aleph_{\omega}$ that fulfills $S$, and much higher cardinals!

Question: What's the exact consistency strength of this theory? And in particular can it interpret $ZFC$ the way Ackermann set theory does?

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  • $\begingroup$ Does $\subset$ here represent $\subseteq$ or $\subsetneq$? $\endgroup$
    – user76284
    Commented Mar 17, 2020 at 18:44
  • $\begingroup$ @user76284, the second.but it doesn't really matter, you can used it for the first for shortness purposes. $\endgroup$ Commented Mar 17, 2020 at 18:45

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