Let $f$ be a polynomial with a super attracting fixed point at $x=0$. Can the immediate basin of attraction of the fixed point contain other roots? If so, please provide a specific example with the immediate basin of attraction. If not, why?

$\begingroup$ How about $z^3z^2$? $\endgroup$ – Mark McClure Feb 24 at 20:20

$\begingroup$ @Mark is zero an attracting fixed point? Is, say, $z=1/2$ attracted to zero? $\endgroup$ – Gerry Myerson Feb 24 at 21:17

$\begingroup$ @Mark is 1 in the immediate basin of attraction of 0? It is not obvious $\endgroup$ – user152801 Feb 24 at 21:35

$\begingroup$ what does super attracting mean ? $\endgroup$ – Piyush Grover Feb 24 at 21:39

$\begingroup$ @Piyush A fixed point is superattracting if the derivative is 0. It means the points in the basin of attraction approach specifically at an exponential rate. In this case, for $z$ in the basin of attraction,$ f(z)0\approx bz0^p$ for some constant p. $\endgroup$ – user152801 Feb 24 at 21:48
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Let $f(z)=az^2(z1)$. Zero is superattracting. Now choose $a$ so small that $f(z)<z/2$ for $z<2$. Then the root $z_0=1$ is in the immediate domain of attraction.