Let $\mathbb S[z]$ be the free $E_\infty$-ring spectrum generated by the commutative monoid $\mathbb N$. That is, $\mathbb S[z] = \Sigma^\infty_+ \mathbb N$.
In Bhatt-Morrrow-Scholze II (https://arxiv.org/abs/1802.03261), they define a map out of this spectrum by choosing an element of the target. In particular, they use the uniformizer $\varpi$ of $\mathcal O_K$ to define a map $\mathbb S[z] \to \mathcal O_K$ by $z \mapsto \varpi$. This occurs in the paragraph after Theorem 11.2. By all indications, this seems to be an $E_\infty$-ring map.
This is not the only place in the literature where such a property of $\mathbb S[z]$ is used. In this paper of Krause--Nikolaus (https://arxiv.org/abs/1907.03477), they define the same map at the beginning of section 3.
However, we know the universal property of $\mathbb S[z]$: it is the free $E_1$-algebra on a single generator. This does not often coincide with the free $E_\infty$-algebra on a single generator. See here or the second answer here.
My questions are the following:
- Are these maps $\mathbb S[z] \to \mathcal O_K$, $z \mapsto \varpi$ actually $E_\infty$-ring maps? Or just $E_1$?
- How do you obtain $E_\infty$-ring maps out of $\mathbb S[z]$? In particular, for which elements of $\Omega^\infty A \simeq \operatorname{Map}_{E_1}(\mathbb S[z], A)$ can we lift an $E_1$-map to an $E_\infty$-map?
- When the target is an Eilenberg--Maclane spectrum, can we obtain an $E_\infty$-map $\mathbb S[z] \to HB$ for any element of $B = \pi_0 HB$?
Ideally, the answer to this second question would come in the form of a natural transformation $\Omega^\infty \to \operatorname{Map}_{E_\infty}(\mathbb S[t], -)$. But this is probably too optimistic.