I have recently come across the book The Kurzweil-Henstock Integral and its Differentials by Solomon Leader, in which, if I understand correctly, the HK integration process is modified in a way that makes it also work for dimensions higher than 1 (there's a proof of Green's theorem at the end). It has always been my impression that HK-integration doesn't extend to n dimensions, but truth be told, I don't actually know why.

So my question(s) is (are):

  1. In what sense can the Henstock-Kurzweil integral not be extended to more than one dimension?
  2. Leader's construction via summants below seems very reminiscent of Jenny Harrison's work on chainlets. Are the two related?
  3. Does the relationship to measures from the one-dimensional case go both ways, i.e. every measure is a differential? Would this relationship be preserved in higher dimensions?

Below I've summarized the key features of Leader's construction.

A cell is a closed interval [a,b] in $[-\infty, \infty]$. A figure is a finite union of cells. A tagged cell in a figure K is a pair (I,t) where I is an interval contained in K, and t is an endpoint of I (according to Leader, the restriction of tags to be endpoints is key).

A gauge is a function $\delta:[-\infty,\infty]\to (0,\infty)$. Every gauge associated to every point t a neighborhood '$N_\delta(t)$ which is $(t-\delta(t),t+\delta(t))$ for finite t, $[-\infty,-\frac1{\delta(-\infty)}]$ and $[\frac1{\delta(-\infty)},\infty]$ for the infinite points. This ensures that $N_\alpha(t) \subset N_\beta(t)$ if $\alpha(t)\leq\beta(t)$, and then we can define division of a figure K into tagged cells to be $\delta$-fine if for each tagged cell $(I,t)$ we have $I\subset N_\delta(t)$.

Then where I understand Leader's theory to take a departure from the normal development, he defines a summant S to be a function on tagged cells, and then he constructs $\int_K S$ of a summant S over a figure K as the directed limit of $\sum_{(I,t)\in\mathcal{K}} S(I,t)$ over gauges $\delta$, where $\mathcal{K}$ are $\delta$-fine divisions of K (he actually defines a limit supremum and a limit infimum and works with those).

Some summants are for example $\Delta([a,b])=b-a$ and $|\Delta|([a,b]=|b-a|$. Any summant S can be multiplied by a function by way of $(fS)(I,t)=f(t)S(I,t)$, and any function can be canonically extended to a summant $f\Delta$.

Where his theory really gets interesting is that he defines differentials as equivalence classes of summants under the equivalence relation $S~T$ if $\int_K|S-T|=0$. From there he defines the differential of any function g by $dg=[g\Delta]$, where $[S]$ is the equivalence class of the summant S.

From this he calls a differential integrable if its representative summants S are integrable, and show that every integrable summant is of the form df where f is a function. Then absolutely integrable summants (ones such that $|df|$ is integrable) give rise to measures. For example, the differential dx, where x is the identity function, corresponds to standard Lebesgue measure.

A final point of interest is that the fundamental theorem of calculus can be formulated as $f\Delta=f'df$ where $f'$ is the usual derivative of f (which I actually think is a great way to motivate the definition of pointwise derivative in the first place).

On to n-dimensional theory, though. An n-cell [a,b] consists of the parallelepiped with opposite vertices (a,a,a,...,a) and (b,b,b,b,...,b). A tagged n-cell (I,t) has tag one of the vertices, it is $\delta$-fine if it's diameter is less than $\delta(t)$. The $\Delta^{(n)}g$ is given by the alternating sum $\sum_{t\in V_I} (-1)^{\mathcal{N}_I(v)}g(t)$, where $V_I$ are the vertices of I, and $N_I(v)$ are the number of coordinates of v that are the same as those of the tag t.

Allegedly (Solomon doesn't give the details in his book), integration goes through, though some results regarding fundamental theorem and such allegedly do not. I am unclear on what happens to the relationship with measures.

  • $\begingroup$ When you write $fΔ=f'df$, presumably you mean $fΔ=f'[dx]$ (or equivalently $[df]=f'[dx]$). $\endgroup$ Jan 29, 2018 at 21:38
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    $\begingroup$ OK, I've got the brackets backwards; in place of $f\Delta=f'df$, you want (if I'm not mistaken) $[f\Delta]=f'dx$, or equivalently $df=f'dx$. (I don't see that you can make the summant $f\Delta$ equal to anything, only its equivalence class $[f\Delta]$, which is $df$.) $\endgroup$ Jan 31, 2018 at 21:28
  • $\begingroup$ Nearly two years later, I've noticed another thing. You say that $[a,b]$ is an interval, and you suggest that $\Delta$ and $\lvert\Delta\rvert$ do different things to it. But if $a\leq b$, then they do the same thing. So I think that, formally, $[a,b]$ is simply a pair of extended real numbers, thought of conceptually as an oriented interval (or parallelogram, parallelepiped, or so on). Which is fine with me. $\endgroup$ Dec 13, 2019 at 13:24

3 Answers 3


This is referring to question 1.

There's a choice we have to make when defining a real-valued two-dimensional (or n dimensional) nonabsolute integral: would we rather have a class of integrable functions which include all divergences of differentiable functions, or would we want to have some sort of Fubini's Theorem working? This conflict was know from the early development of the HK integral and was also pointed out by Pfeffer in the book mentioned in Gerald Edgar's answer.

If we define the HK integral in the obvious way (call it the standard two dimensional HK integral), we get Fubini's theorem, but no fully general divergence theorem. Many authors made modifications on the definition of this integral, and an relatively satisfactory definition was given by Jarník, Kurzweil and Schwabik in "On Mawhin's approach to multiple nonabsolutely convergent integral", Casopis. Pest. Mat. There they defined the $M_1$-integral, which satisfies a fully general divergence theorem, and has a simple enough definition so we can prove some convergence theorems. It is shown though that this integral does not satisfy Fubini's theorem when the corresponding one-dimensional integrals are considered to be the HK integral. The original example from that paper can be used to show that, in a more general setting, an interval-based two-dimensional integral that satisfies a full divergence theorem will fail in some sense Fubini's theorem (see Proposição 2.5 here if you are not afraid of reading in portuguese).

Other problem that is frequently overlooked when defining interval-based two-dimensional nonabsolute integrals is that the integral can be sensitive to rotations, that is, we can get integrable functions such that a certain rotation of that function is not integrable. We have this unpleasant effect for the $M_1$-integral and even for the standard two-dimensional HK integral (see main theorem of "K theorii vícerozmerného integrálu", Casopis. Pest. Mat. by K. Kartak, if you are not afraid of reading Czech, or Proposição 1.7 in the aforementioned Thesis, which is for the $M_1$-integral but easily adaptable to the standard two-dimensional HK one).

Then there is a new challenge: trying to define an integral which is not based on intervals but that still will be simple enough to prove convergence theorems. Kurzweil himself defined an integral where the domain is partitioned into sets with boundaries continuously differentiable by parts; it's a lot of trouble even to prove Saks' Lemma for this integral. See also this article (Triangle Integral–A Nonabsolute Integration Process Suitable for Piecewise Linear Surfaces by Ricardo Bianconi and Pedro L. Kaufmann, projecteuclid) for an integral where we use triangular partitions. This integral satisfies many of the commonly desired theorems, but it is unknown to me for example if it satisfies a nice change of variables formula.

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    $\begingroup$ The cited Proposição 2.5 says that there is a function which is integrable in 2 dimensions with integral zero, and one of whose iterated integrals is also zero, but the other iterated integral does not exist. That shows we can't have a Fubini theorem of the sort "the integral of any integrable function can be calculated as an iterated integral". But what about a theorem such as "if an iterated integral exists, then it is equal to the multidimensional integral"? $\endgroup$ May 16, 2014 at 21:03

A reasonable method of defining an integral that includes the HK integral is to say a Schwartz distribution $f$ is integrable if it is the distributional derivative of a continuous function $F$. Then the integral $\int_a^b f =F(b) - F(a)$. The resulting space of integrable distributions is a Banach space that includes the space of HK integrable functions and is isometrically isomorphic (with Alexiewicz norm) to the continuous functions vanishing at a (with uniform norm). In Euclidean spaces one does much the same but integrable distributions are those that are the distributional derivative taken once in each Cartesian variable. Again, we get a Banach space of integrable distributions. A Fubini theorem holds but the only transformations that can be done are those that map Cartesian intervals to Cartesian intervals. This rules out rotations. For details, see D.D. Ang and L.K. Vy, On the Denjoy--Perron--Henstock--Kurzweil integral, Vietnam J. Math. 31 (2003), 381--389.


There is a chapter on this (multi-dimensional gauge integral) in: W. Pfeffer, The Riemann Approach to Integration (Cambridge, 1993)


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