Schramm's formula on left passage probabilities of $SLE_k$ is stated for $k \in [0,8)$ in theorem 2 here. However, after the statement he remarks that the formula simplifies to $1/2$ for $k = 8$. It seems that at the time of that paper, it was not known that the $SLE_k$ trace existed for $k = 8$ (second paragraph of third page of Schramm's article). However, it was later discovered that there is a continuous trace for $k = 8$, which arises as the scaling limit of the Peano curve of a uniform spanning tree.
Question: Is it true that the left-passage probability for the $SLE_8$ trace is $1/2$? Is there a reference that proves this?
Edit: Dmitry Krachun points out that it's not clear that there is a good meaning for left-passage probabilities, since $SLE_8$ is space filling. Schramm's definition for left-passage probabilities makes sense for any $\kappa < 8$, because for $\kappa < 8$ and any fixed $z_0$, $\mathbb{P}( z_0 \in \gamma( [0, \infty)) | \gamma \in SLE_{\kappa} ) = 0$. Nonetheless it seems possible that there is some interpretation of the left-passage probability being $1/2$, perhaps arising from the Peano curve approximation.
In the wikipedia article for the left-passage probabilities, no restrictions on $\kappa$ are given. Is this correct? No reference is provided.