1
$\begingroup$

Suppose I parametrize complex plane by coordinates,$$z = x+i y,\ \bar z=x-i y$$ then the upper half plane, $\mathbb H_+$ is given by $y>0$. I am looking for chiral coordinate transformations, $f(z)$, such that

  1. they map the boundary ($y=0$) to itself,$$f(z)=\bar f(\bar z) \ \text{whenever } z=\bar z~.$$
  2. $z+\bar z >0 \Leftrightarrow f(z)+\bar f(\bar z)>0~.$

Since there is a conformal map between $\mathbb H_+$ and unit disc (Poincare disc), $\mathbb D = \{w:|w|<1\}$, where the above conditions become:

  1. the coordinate transformations map the boundary of $\mathbb D$ ($|w|=1$) to itself,$$g(w) \bar g(\bar w)=1 \ \text{whenever } w\bar w=1~.$$
  2. $w \bar w<1 \Leftrightarrow g(w)\bar g(\bar w)<1~.$

The Schwarz-Pick Lemma seems to suggest that a general holomorphic transformation brings the boundary of the disc closer than $1$ in the Poincaré metric (I am interested in AdS$_2$ so I can equivalently say that the new boundary after the coordinate transformation is at a finite distance from any interior point),$$\frac{g'(w)\bar g'(\bar w)}{\left(1-g(w)\bar g(\bar w)\right)^2}dw d\bar w \le \frac1{(1-w\bar w)^2}dw d\bar w$$ and the equality folds only for Mobius transformations (which can be seen as isometries of AdS$_2$).

  • Is it correct to deduce that there are no (non-trivial, of course not the Mobius transformation) holomorphic transformations that satisfy the conditions 1 and 2 above, or am I interpreting the Schwarz-Pick lemma incorrectly?
  • If my interpretation of Schwarz-Pick lemma is correct and there are no holomorphic maps with the given constraints, then what are the less restrictive class of functions that obey the above constraints?

PS: I have also asked the same question in Physics.SE here. I hope this doesn't violate any rules.

$\endgroup$
  • 5
    $\begingroup$ I have to admit I'm having slight troubles understanding what exactly you're asking, but if one part of the question is, what are the (biholomorphic) automorphisms of the unit disk (or, equivalently, upper half plane), then indeed, this is exactly the Moebius transformations. $\endgroup$ – Christian Remling May 30 at 20:53
  • $\begingroup$ Yes, that is indeed part of my question: whether only biholomorphic functions that map unit disc to itself (I wasn't calling it automorphisms was because I thought that was same as isometries, and I didn't want isometries) are Mobius transformations. The second part of my question is what are the minimum amount of constraints that I should relax to find a non-trivial function (not Mobius transformation) that maps disc to itself? $\endgroup$ – nGlacTOwnS May 30 at 23:09
  • 1
    $\begingroup$ I don't think this second part has a good answer (or rather the answer is uninteresting): just dropping analyticity, so for instance looking only for diffeomorphisms of the unit disk, will give you a huge supply of extra examples, in addition Moebius transformations. $\endgroup$ – Christian Remling May 31 at 1:45
5
$\begingroup$

The class of holomorphic maps satisfying 1 and 2 is well known and is frequently used. Let us begin with rational functions satisfying 1,2. They are all of the form: $$az+b-\sum_{n}\frac{c_n}{z-z_n}$$ where $a\geq 0$, $b$ is real, $c_j\geq 0$ and $z_j$ are real. And this is a parametric description (every such function satisfies 1, 2). To get rid of the restriction that $f$ is rational, one passes to the limit. The result depends on your exact assumptions. If you want your function to be meromorphic in the plane, you obtain a similar formula, with finite sum replaced by an infinite sum. If you want a function which is only holomorphic in the upper and lower half planes, then you replace the sum by an integral. The most general formula which gives a holomorphic function in the union of upper and lower half-planes, and maps each half-plane into itself is $$az+b+\int_{-\infty}^\infty\left(\frac{1}{t-z}-\frac{t}{1+t^2}\right)d\mu(t),$$ where $\mu$ is any non-decreasing function of finite variation on the real line. (The extra term is added to make the integral convergent). As above, this is a parametric description. As you say, these formulas can be transplanted to describe the corresponding classes in the unit disk. These are called additive representations.

There are also multiplicative representations (which are more convenient to write for the unit disk). For example, a rational function $f$ which satisfies $|f(z)|<1$ in the unit disk and $|f(z)|>1$ outside, is a Blaschke product: $$f(z)=e^{i\theta}\prod_n\frac{|a_n|}{a_n}\frac{z-a_n}{1-\overline{a_n}z},$$ where $\theta$ is real nd $|a_n|<1$. This can be generalized to infinite products, and to an integral. The general multiplicative representation is $$f(z)=B(z)\exp\left(\frac{z+e^{it}}{z-e^{it}}d\mu(t)\right),$$ where $B$ is Blaschke product, finite or infinite, and $d\mu$ is a (non-negative) measure on the unit circle.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.