Let $X$ be an integral Noetherian separated scheme. Can there exist two morphisms of finite type $X\rightarrow \mathrm{Spec}\,\mathbb{C}$ such that the corresponding complexanalytic spaces are not weakly homotopy equivalent?
$\begingroup$
$\endgroup$
2

2$\begingroup$ If one changes the structure morphism by an automorphism of $\mathrm{Spec} \mathbb{C}$ then the (topological) fundamental group can change (as first shown by Serre). $\endgroup$– nafMay 19, 2019 at 11:40

$\begingroup$ Probably related: meta.mathoverflow.net/questions/4200/floodofnewusers $\endgroup$– YCorMay 31, 2019 at 14:16
Add a comment
