# The (topological) fundamental group of (quasi)-projective algebraic varieties

I would like to know:

What does the fundamental group of a quasi-projective algebraic variety look like?

I remember that I have seen somewhere that for a connected, finite-type CW-complex $$X$$, its fundamental group is the direct product of a free group of finite rank and a finite abelian group.

Is this statement true? Why?

• The statement you wrote is not true. Pick a torus as a counterexample (the fundamental group is $\mathbb{Z}\oplus\mathbb{Z}$). In fact every finitely presented group is the fundamental group of some connected finite CW of dimension at most 2. – Denis Nardin Apr 24 at 11:43
• $\mathbb{Z}\oplus\mathbb{Z}$ is a free abelian group, not a free group. – Denis Nardin Apr 24 at 11:46
• I do mean a complex torus (which topologically is just a torus). – Denis Nardin Apr 24 at 11:50
• There are indeed restrictions on the fundamental group of smooth complex algebraic varieties, besides being finitely presentable. The first known one is described in a paper of J. Morgan, The topology of Algebraic Varieties. If you drop "smooth" then any finitely presented group can appear. Other restrictions are known but no complete characterization. What is the precise question? – Louis-Clément LEFÈVRE Apr 24 at 12:16
• – Misha Apr 24 at 14:41

Much of the OP's questions were addressed in the comments. Here is a summary with some additional references and remarks.

In Hatcher's book Algebraic Topology, Corollary 1.28 states (which follows from van Kampen's Theorem): For every group $$G$$ there is a 2-dimensional cell complex $$X_G$$ with $$\pi_1(X_G)\cong G$$. In particular, if $$G$$ is finitely presentable, then there is a finite CW complex with $$G$$ as its fundamental group.

So your statement "a connected, finite-type CW-complex $$X$$, [has] it's fundamental group the direct product of a free group of finite rank and a finite abelian group" is about as false as possible.

Moving on, if one allows singularities, then Simpson proved in 2010 that for every finitely presentable group $$G,$$ there exists an irreducible projective variety with that fundamental group (Theorem 12.1). He asked whether this can be done with restrictions on the singularities. Using a result of Goldman and Millson, Kapovich and Kollár show in 2011 that for every finitely-presented group $$G$$ there is a complex, projective surface $$S_G$$ with simple normal crossing singularities only such that $$\pi_1(S_G)\cong G$$ (Theorem 2). However, they did not prove $$S_G$$ could be taken to be irreducible. So a year later (2012), Kapovich shows: for any $$G$$ that is finitely-presented, there exists a 2-dimensional irreducible complex-projective variety $$W$$ with the fundamental group $$G$$, so that the only singularities of $$W$$ are normal crossings and Whitney umbrellas (Theorem 1.2).