2
$\begingroup$

Let $X$ be a Banach lattice and let $K=\{x^{*}\in B_{X^{*}}:x^{*}\geq 0\}$. Then $K$ is a compact Hausdorff space under the $weak^{*}$-topology. Let $\mu$ be a regular Borel probability measure on $K$. We denote by $i_{X}$ the embedding $X\rightarrow C(K)$ given by$\langle i_{X}(x),x^{*}\rangle=\langle x^{*},x\rangle, x\in X, x^{*}\in K.$ It is easy to see that $i_{X}$ is an isomorphic embedding.

Let $1\leq p<\infty$. Let us define a seminorm $|||\cdot|||$ on vector space $i_{X}(X)$ by $$|||f|||=[\int_{K}\langle x^{*},|x|\rangle^{p}d\mu(x^{*})]^{\frac{1}{p}}, f=i_{X}(x)\in i_{X}(X).$$ We set $$R=\{f\in i_{X}(X):|||f|||=0\}.$$ Then $i_{X}(X)/R$ becomes a normed space under the norm $$\|[f]\|=|||f|||,f\in i_{X}(X).$$ Let $L^{p}_{0}(\mu)$ be the completion of the normed space $(i_{X}(X)/R,|||\cdot|||)$.

Question 1. what's the dual of $L^{p}_{0}(\mu)$?

Question 2. Is $L^{p}_{0}(\mu)$ reflexive for $1<p<\infty$?

Question 3. Is $L^{p}_{0}(\mu)$ an $\mathcal{L}_{p}$-space?

Thank you!

$\endgroup$

0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Browse other questions tagged or ask your own question.