Squares in the set $\{\sum_{j=1}^m j^2: m\in\mathbb{N}\}$ [closed]

Are there infinitely many squares in the set $$\{\sum_{j=1}^m j^2: m\in\mathbb{N}\} ?$$

We have $$\sum_{j=1}^m j^2 = \frac{m(m+1)(2m+1)}6$$. Hence, the question reduces to finding integral points on the elliptic curve: $$y^2 = \frac{x(x+1)(2x+1)}6.$$ Turning it to Weierstrass equation with integer coefficients, we get: $$(72y)^2 = (12x)^3 + 18 (12x)^2 + 72 (12x).$$
sage: EllipticCurve([0,18,0,72,0]).integral_points()

So, the only solutions are $$m=\frac{0}{12}=0$$, $$m=\frac{12}{12}=1$$, and $$m=\frac{288}{12}=24$$.