I am looking for the easiest possible example of a connected covering $X\to X/\mathfrak{S}_3$ ($\mathfrak{S}_3$ the third symmetric group). More precisely, I want $X$ and $X/\mathfrak{S}_3$ to be small finite complexes and the covering to be cellular. I would be happy if I have a concrete description of the attaching maps of $X$ and how $\mathfrak{S}_3$ permutes the cells of $X$.
1 Answer
Here is a picture from Topology and Groupoids
It is meant to show in (i) the Cayley graph of the presentation $\mathcal P$ of $G=S3$, $\{x,y:x^3,y^2,xyxy\}$. The Cayley graph is the $1$-skeleton of the universal cover of the cell complex $K(\mathcal P)$ of the presentation. The picture (ii) is a chosen tree in the Cayley graph. The diagram shows 3 rectangles, 2 triangles, and 3 "2-gons". Since $K$ has three 2-cells, corresponding to the relations, the universal cover will have eighteen 2-cells.
FKranhold's comment seems quite correct. A full algebraic explanation is given in Section 10.3.ii of the book Nonabelian Algebraic Topology (NAT) using free crossed modules and resolutions, and covering morphisms of groupoids. (It may seem extreme to recommend these concepts from this thick book, but these are the algebraic concepts relevant to the cellular geometry!)
If we set $r=x^3, s = y^2, t=xyxy$ in $F(x,y)$, the free group on $x,y$, the free crossed module $\delta: C(r,s,t) \to F(x,y)$, maps $r$ to $x^3$, $s$ to $y^2$, $t$ to $xyxy$, modelling the boundaries of the 2-cells of $K(\mathcal P)$ . The kernel of $\delta$ is isomorphic to the second homotopy group $\pi_2(K(\mathcal P), *)$.
The algebraic modelling procedure is also helped by using groupoids and covering morphisms of groupoids.
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$\begingroup$ Thank you! Am I correct that the Cayley graph (i) is an $\mathfrak{S}_3$-covering of $\mathbb{S}^1\vee\mathbb{S}^1$ as suggested by Gustavo and $\mathfrak{S}_3$ acts as follows: $x$ rotates the triangle by $120^\circ$ and $y$ inverts inner and outer and reflects once? And is it correct that adding the three $2$-cells (resp. eighteen $2$-cells above) gives another $\mathfrak{S}_3$-covering which is the universal covering of the base? And that we have two $2$-cells per bigon and $4$-gon and three for each of the two triangles? $\endgroup$ Commented Apr 4, 2019 at 8:09