We know Lang conjecture can imply uniform boundless of rational points on higher genus (smooth projective) curves over a fixed number field by works of Mazur and others.

How is the conjecture of uniform boundness now? Are there some new results?

  • 1
    $\begingroup$ Michael Stoll proved this assuming the Zilber-Pink conjecture (ems-ph.org/journals/…), and Katz-Rabinoff-Zuerick-Brown proved this for all curves satisfying $r \leq g-3$, where $r$ is the Mordell-Weil rank of the curve and $g$ is the genus (projecteuclid.org/euclid.dmj/1476450482) $\endgroup$ – Stanley Yao Xiao Mar 23 at 4:45
  • 2
    $\begingroup$ @StanleyYaoXiao What I actually prove assuming Zilber-Pink is that there is a uniform bound in terms of $g$ and $r$ for the number of (geometric) points on a curve of genus $g$ mapping into a subgroup of rank $r$ of (the geometric points of) its Jacobian. So if you assume Zilber-Pink and a uniform bound on the Mordell-Weil rank of Jacobians of curves of genus $g$, uniform boundedness of the number of rational points follows. $\endgroup$ – Michael Stoll Mar 23 at 13:12
  • 1
    $\begingroup$ (continued:) What Katz, Rabinoff and Zureick-Brown do (extending results for hyperelliptic curves in my paper) is to prove an unconditional result like this for $p$-adic points and assuming that $r \le g-3$. The bound depends on $g$ and the $p$-adic field considered. $\endgroup$ – Michael Stoll Mar 23 at 13:15
  • 1
    $\begingroup$ See also mathoverflow.net/questions/215111/… and mathoverflow.net/questions/103327/… . $\endgroup$ – Michael Stoll Mar 23 at 13:21
  • $\begingroup$ @MichaelStoll Thank you a lot ! $\endgroup$ – zzy Mar 24 at 0:00

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.