2
$\begingroup$

There is the general construct of a fibre bundle induced by a topological group action. Yet, one of the distinctive differences between this notion and the notion of a vector bundle is that the base space of the former need not be locally Euclidean.

It seems preferable to have a generalisation that would allow for something like a $C^{-1}$-manifold, ie. a manifold that is not locally Euclidean at all, in order to have statements that encompass both the case of vector bundles and the case of general $(F,G)$-bundles (where $F$ is the local space, ie. the analogue of the vector space of the vector bundle, an $G$ is the group).

Does such a concept exist? If so, what is its name?

$\endgroup$
3
  • $\begingroup$ An example would be any statement such as the one associated to the so-called "clutching construction", where one takes a clutching map and makes a vector bundle out of it. Here, if one works with differentiable manifolds, one has to keep track of differentiability; otherwise, this issue is not important. If one had a concept of different degrees of differentiability including continuity and total absence of Euclidean structure, then one could unify the construction. $\endgroup$
    – Cloudscape
    Feb 20, 2019 at 20:49
  • $\begingroup$ I don't think I understand the question. A topological vector bundle can be defined over any topological space. If it is defined over a manifold, it can be smooth (but does not have to be). Also, what is a manifold if not locally Euclidean? $\endgroup$ Feb 21, 2019 at 21:41
  • $\begingroup$ @SebastianGoette "what is a manifold if not locally Euclidean?" - exactly. All the computations that need the object to be locally Euclidean are as yet specific to the case where the base space is at least a manifold; often $G$ is a Lie group and $F$ is a manifold, such as a vector space (in the case of vector bundles). I'm trying to find a concept that unifies all these cases, thus making it possible to treat them uniformly. (This may necessitate the use of the concept of vacuous truth at some places.) I could come up with such a concept, but I'd prefer to use an existent one. $\endgroup$
    – Cloudscape
    Feb 22, 2019 at 14:45

0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Browse other questions tagged or ask your own question.