We consider the f-divergence, which takes the form $$ D_f(P \| Q) = \int_\Omega f\left(\frac{dP}{dQ}\right) dQ. $$ For example, when $f(t) = t \log t$, we obtain the KL-divergence.

My question is that, as a function of $P$, under what regularity conditions on $f$ and $Q$ is the f-divergence $D_f(P \| Q)$ (geodesically) $\mu$-smooth with respect to the Wasserstein metric $W_2$?

For any function $g(P)$, the (geodesic) $\mu$-smoothness of $g(P)$ takes the form $$ g(P') \leq g(P) + \langle\text{grad}\,g(P), \exp_P^{-1} (P') \rangle_P + \frac{\mu}{2}\cdot W_2^2(P, P') $$ or equivalently that the Hessian $\text{Hess}(g)$ is bounded from the above by $\mu$ for all $P$. Here, $\text{grad}$ and $\text{Hess}$ are the gradient and Hessian with respect to the $W_2$ metric, which is the geodesic distance in the space of probability distributions, and $\exp_P^{-1} (P')$ is the inverse of the exponential map.