Let $G$ be a connected, reductive group over a local field $k$, and let $^LG$ be the Langlands dual group. As explained by Borel in his article in the Corvallis proceedings, the general local Langlands correspondence should give (1) a partition of the classes of irreducible admissible representations of $G(k)$ into finite sets, called L-packets and (2) a bijection between the L-packets and the equivalence classes of admissible homomorphisms of the Weil-Deligne group $W_k'$ into $^LG$.
The bijection should be such that if $r$ is a finite dimensional complex representation of $^LG$ whose restriction to $^LG^{\circ}$ is complex analytic, and $\pi$ is a member of an L-packet corresponding to an admissible homomorphism $\rho$, then we should have an equality of L and epsilon factors
$$L(s,r \circ\rho) = L(s,\pi,r)$$
$$\epsilon(s,r \circ \rho,\psi) = \epsilon(s, \pi,r,\psi)$$
whenever the objects on the analytic side can be defined.
The conjectural correspondence $\{\pi\} \rightarrow \rho$ seems unsatisfactory to me for the following reason: the L-group $^LG$ does not change if we replace $G$ by an inner form. This is on account of the fact that the group of inner automorphisms of $G_{\overline{k}}$ act trivially as automorphisms of the based root datum of $G_{\overline{k}}$.
If $G'$ is an inner form of $G$, the groups $G(k)$ and $G'(k)$ and their representations should look completely different. However, if we take the local Langlands correspondence as I stated it above at face value, there should be correspondences between these representations giving them the same L-functions and epsilon factors.
Do we really expect the representations of different forms of algebraic groups to be give the same L functions and epsilon factors? Or do we expect there will eventually be more complicated formulation of the local Langlands correspondence which takes into account different inner forms?