This is a refinement (perhaps a simpler version) of a question I asked here before and couldn't get an answer for.

Fix $\alpha \in (0,1]$ and a small constant $c>0$. For $x \in [0,1]$ and $N\in\mathbb{N}$, we denote by $S(x,N)$ the function that counts the number of pairs of integers $(p,q)$ such that $$|x-\frac{p}{q}|<\frac{c}{q^{\alpha+1}}\qquad(\star)$$

and $1\leq q \leq N$, $gcd(p,q)=1$.

It is known that when $\alpha=1$, all the solutions $(p,q)$ to $(\star)$ are in fact the convergents (i.e. truncation of the continued fraction expansion of $x$). The recursive formula for the denominators of those implies that they grow exponentially (asymptotically), and for all irrationals at least as fast as those for $x$ being the golden ratio (you can consider its fractional part in order to have it in the interval). This, in turn, implies that there exists some constant $C>0$ such that
$$||S(x,N)||_{L^{\infty}([0,1])}\leq C \log N.$$

I'm interested in getting an upper bound on this $L^{\infty}$ norm for any $\alpha\in(0,1)$. To be more precise, I wish to show that this bound is sublinear in $N$.

W. Schmidt considered the more general case where the restriction $gcd(p,q)=1$ is dropped (I denote the corresponding counting function by $M(x,N)$). His asymptotic estimate, which holds for almost every $x\in[0,1]$ is $$M(x,N)\leq \sum_{q=1}^{N} \frac{c}{q^{\alpha}}+C(x) (\sum_{q=1}^{N} \frac{c}{q^{\alpha}})^{\frac{1}{2}}.$$
But as far as I can tell, the function $C(x)$ is unbounded, so there is no uniform bound.

One can also try and apply first and second moment estimates on the function $S(x,N)$ (using Chebyshev's inequality). This gives the desired sublinear estimate, but only up to some exceptional subset of $[0,1]$ which turns out to be too big for my purposes.

There seems to be a large gap between the case $\alpha=1$, where everything is known, and smaller values of $\alpha$, which I can't explain at the moment.

-- Addition --

This might be a trivial comment, but it should be emphasized that the trivial bound is $$||S(x,N)||_{L^{\infty}([0,1])}\leq C\cdot N.$$ So I'm really looking for any kind of nontrivial bound.