This is more like an optimization problem but any solution is appreciated.

I have a data set with input specifying power(demand) to be generated for a particular time period(TP).

Time --- Power
01 to 02 1000
02 to 03 2000
03 to 04 2000
04 to 05 1500

But the power can't just be increased from 1000 to 2000 at 01:59:59. Here there will be some ramping rate(gradient) which I want to minimise by keeping the imbalance to 0. Imbalance may arise if you deviate from what is needed, here power cannot be more or less than what is required in that Time Period.

In summary I have to generate the black line(which is output) below (red line is the input). enter image description here

I am trying to get an output which can be a curve(black line) equation or the power to generate at the deflection points(say at around 1:45 we generate 800 then at 2:15 it can be 2200 which will keep the imbalance to 0).

When I tried to treat this as an optimization problem it may look something like this:
Objective : Minimise gradient f(x) = Yj-Yi/Xj-Xi between 2 points (Xi,Yi) and (Xj,Yj)
Subject to constraints:

average of Yi = Power value(redline in that Time Period)

But I am struggling to complete it how to represent mathematically to be able to implement using programming like R's lpsolve/optimize or Python's scipy optimizers.

Any help on the approach to take would be greatly appreciated.

  • What is MCNN and why is the value 1000 MWh written in red cut with a line, only to be rewritten below in black? Did you mean, say, 800 MWh? – Alex M. May 15 at 12:17
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    This is really not the right place for this question. – orlp May 15 at 12:30
  • @orlp: It might be, if the OP manages to clarify some bits of his question. Remember that mathematical research is not only about the Hasse-Weil Zeta function. Applied mathematics fits the profile of this site as well. – Alex M. May 15 at 12:43
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    @AlexM. My concern is not that it is applied mathematics, but that (to my eye) it is not research-level. – orlp May 15 at 13:13
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    So many suggestions why "it is not research level" and where to put it and no simple and clear instruction how to draw the curve. Shame on us! I have almost no time now, so I'll just type the recipe within the next hour. I'll explain the logic behind it later. – fedja May 15 at 18:26

Here is just a recipe. It has its advantages and disadvantages, so try to implement it and see if it gives what you want or there are some undesirable features. It minimizes the integral of the gradient squared on a long run while preserving the average over each interval $[k,k+1]$ where $k$ is an integer.

1) Compute the coefficients $a_k=\frac 1{2\pi}\int_0^{2\pi}\frac{3\cos kt\,dt}{2+\cos t}$, $k=0,1,2,\dots$. About $10$ of them should be enough for decent precision.

2) Define $f(x)$ to be $0$ if $x\le-1$; $(x+1)^2/2$ if $-1\le x\le 0$, $1-(1-x)^2/2$ if $0\le x\le 1$, $1$ if $x\ge 1$.

3) Define the "elementary response" $$ g(x)=a_0 f(x)+\sum_{k\ge 1} a_k[f(x-k)+f(x+k)]\,. $$

4) If your time interval is $[0,T]$, then your curve is $$ Y(x)=\text{Average}_{[0,1]}Y+\sum_{t=1}^{T-1} \Delta Y(t) g(x-t) $$ where $\Delta Y(t)$ is the difference of the averages over $[t,t+1]$ and $[t-1,t]$ (so the elementary response corresponds to the output that is $0$ for negative times and $1$ for positive times).

Test it and let me know if you have any problems with this solution.

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