5
$\begingroup$

A construction encountered in the Dijkgraaf-Witten invariant uses the following ingredients:

  • An oriented, (assumed here to be smooth) manifold $M^n$
  • A finite group $G$ (and a field, chosen to be $\mathbb{C}$ here)
  • An $n$-th cohomology class $[\omega] \in H^n(G, U(1))$ (where $U(1)$ is considered as a discrete group here)
  • A homomorphism $\phi\colon \pi_1(M) \to G$

There is a canonical (up to homotopy) map $c\colon M \to B\pi_1(M)$. We can then abstractly construct the cohomology class $c^* \phi^* ([\omega]) \in H^n(M, U(1))$.

I'm interested describing this cohomology class very concretely. Assume I have given:

  • $M$ as a handle decomposition (and consequently we consider Morse cohomology, where the $k$-th grade of the complex is generated by the $k$-handles)
  • $\phi$ as an assignment of group elements to each 1-handle of $M$ (satisfying the relations for 2-handles)
  • $[\omega]$ represented through a concrete cocycle $\omega\colon G^n \to U(1)$, i.e. a cocycle in the simplicial cohomology of $BG$

How can I explicitly pull back $[\omega]$ along $\phi \circ c$?

Some remarks:

  • A handle decomposition of $M$ also gives a CW-complex, I think. So $c\colon M \to B\pi_1(M)$ can be chosen canonically as a cellular map via the Postnikov construction, and it's the pullback on cohomology can be derived from the pullback on the level of complexes.
  • The trouble seems to be that $\phi$ isn't obviously cellular on higher cells if we describe $BG$ as a simplicial complex (which we might have to at some point because $[\omega]$ is given that way).
$\endgroup$

0

You must log in to answer this question.