1
$\begingroup$

Lebesgue theorem says that a bounded function $f$ is Riemann Integerable if and only if $f$ continuous almost everywhere.

Unfortunately, we know a function has antiderivative has no relation to Riemann Integerable.

Q. Is there some nice equivalent condition to the fact that a real function has antiderivates?

$\endgroup$

1 Answer 1

1
$\begingroup$

There are various characterizations of real functions which have antiderivatives. See, for example, Theorem 4 in M. W. Botsko: Exactly which bounded Darboux functions are derivatives?, Amer. Math. Monthly 114 (2007), 242-246.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .