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Let $f$ be a continuous fonction from $\mathbb R$ to $\mathbb R^2$, such that for any $a<b\in \mathbb R,\,\, f([a,b])$ is convex.

Is there a line $D\subset \mathbb R^2$ such that $f(\mathbb R)\subset D$ ?

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  • $\begingroup$ The linked "duplicate" does, indeed, have two answers. However, neither of them answers the question. But perhaps one of the comments does provide a reference for an answer? $\endgroup$ Commented Feb 24, 2018 at 1:21
  • $\begingroup$ I didn't read the related articles yet, but I'm quite happy with the result announced in the comment of Jairo Bochi. If you ask only $f([0,t])$ to be convex for all $t\in \mathbb R_+$, then there is a counterexample! I also like answers but I have to read the related articles before saying something about the fuzzy direction and ideas that are coming to me right now... I will complete this comment If I find relevant observations from this reading. $\endgroup$
    – jcdornano
    Commented Feb 24, 2018 at 1:51

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