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I was studying about the Hecke algebra from Bernstein's notes on p-adic representation theory and various other sources. First a disclaimer: everything below is fairly new to me so please feel free to correct me in the probably various places I am wrong)

I am trying to make some basic computations, like for example compute the whole algebra probably, $H_K$ (the left-invariant on $K$ distributions) and the center (which in the rest of literature is what is usually denoted by $H_K$ I think, essentially the bi-$K$-invariant distributions). Now the center can be computed by the Satake isomorphism (and it is isomorphic to $\mathbb{C}[z_1^{\pm},z_2^{\pm}]^{S_2}$). For the rest I really could not come up with an explicit computation.

Now searching around, I found that most sources do not define the Hecke algebra as the locally constant compactly supported distributions, but by a purely algebraic definition with some generators over the Weyl group. I really cannot understand this definition.

Can you provide me with some source that explains this explicit presentation of the Hecke algebra, and why is it the same as Bernstein's one?

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    $\begingroup$ You're talking about the Iwahori-Hecke algebra, I presume? Maybe look at the answers to the question here: mathoverflow.net/questions/40305/… $\endgroup$
    – Marty
    Commented Feb 14, 2018 at 7:32

2 Answers 2

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Let $G$ be a reductive $p$-adic group. First fixing a Haar measure on $G$, you can identify the algebra of distributions of $G$ with the ("big") Hecke algebra $H(G)$ of locally constant complex functions with compact support equipped with convolution $\star$. If $K$ is any compact open subgroup, the bi-$K$-invariant functions form a subalgebra $H(G,K)$, called the $K$-spherical Hecke algebra. More generally if $\rho$ is an irreducible smooth representation of $K$, you may form the subalgebra $H(G,\rho ) = e_\rho \star H(G)\star e_\rho$, where $e_\rho \in H(G)$ is the idempotent attached to $\rho$. Note that $H(G,K)$ corresponds to the particular case where $e_\rho$ is the trivial character.

All these algebras are called Hecke algebras. On the other hand there are standard Hecke algebras defined in an algebraic manner via generators and relations, like Iwahori-Hecke algebras.

You cannot expect to understand any sort of Hecke algebra in a naive approach. Any progress in the description of these algebras rely on a very fine understanding of the structure of $G$ (in particular of the double coset set $K\backslash G/K$) as well as a deep understanding of the structure of the representations. In general one wants to find an explicit isomorphism between an Hecke algebra that one wants to understand with a standard Hecke algebra.

Historically the first results concerned the spherical Hecke algebra $H(G,K)$, where $K$ is a "special" maximal subgroup of $G$ (because of its importance in the theory of automorphic forms) via the Satake isomorphism and the Iwahori Hecke algebra (when $K$ is an Iwahori subgroup), because of its importance in the study of unramified principal series.

The general understanding of the Hecke algebras that arise from reductive $p$-adic groups is one of the aims of Type Theory as conceptualized by Bushnell and Kutzko. It turns out that a lot of those Hecke algebras are in fact isomorphic to (or at least Morita equivalent to) standard Hecke algebras! But this is not trivial: this is the result of decades of research starting in the $50$'s.

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  • $\begingroup$ I think I understand what I got wrong, but while I think I found the Bernstein presentation in the Haines-Kottwitz-Prasad paper (arxiv.org/pdf/math/0309168.pdf) and various other sources (with different notations) I can't see why it yields the same result. Could you show in this simple case (for either $GL_2$ or $SL_2$) the explicit description of the Hecke Algebra through the presentation? $\endgroup$ Commented Feb 21, 2018 at 4:22
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A Hecke algebra, in the most common definition, is associated to a pair of groups $G$ and $K$, and is the convolution algebra of bi-$K$-invariant distributions on $G$.

As far as I know the left-invariant distributions are never considered to be a Hecke algebra. This algebra has a highly degenerate structure, because if $a,b$ are distributions and $a'$ is the average of the right translates of $a$ by elements of $K$, then $ab=a'b$, so $(a-a')b$ is zero. So the algebra has a huge space of zero-divisors, and in particular does not have a unit. If you mod out by the degenerate elements $a-a'$, you obtain the usual Hecke algebra of bi-invariant functions.

The definitions you see involving the Weyl group are most likely Iwahori-Hecke algebras, as Marty points out. In this case we would take, if $F =\mathbb Q_p$, $K$ to be the subgroup of elements of $GL_2(\mathbb Z_p)$ that are congruent to upper-triangular matrices mod $p$.

In addition to the link Marty provided, I think your idea of trying to work out at least some of the calculations yourself in the $GL_2$ case is a good one, by using the Bruhat decomposition to find $K \backslash GL_2 (F) / K$ and then computing the products of some double cosets.

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  • $\begingroup$ As I said I probably have some misconceptions...The basic differencein what I've seen is that Iwahori-Hecke algebra is commutative while the "normal" hecke algebra is not (and I think the first is the center of the second by some Bernstein theorem?) $\endgroup$ Commented Feb 14, 2018 at 20:27
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    $\begingroup$ @KostasPsaromiligkos It's the other way around, the usual Hecke algebra is commutative - it's given by what you wrote down with the Satake isomorphism - and the Iwahori-Hecke algebra is not. $\endgroup$
    – Will Sawin
    Commented Feb 14, 2018 at 21:14
  • $\begingroup$ I understand now. Well I think I understand how the Satake transform works, but even using the Bernstein presentation immediately should give the result for both the whole algebra (without fixing a K) and the center (H(G,K)) right? Can you explain to me in this simple case how does the Bernstein presentation give $\mathbb{C}[z_1^{\pm},z_2^{\pm}]^{S_2}$? $\endgroup$ Commented Feb 21, 2018 at 4:19
  • $\begingroup$ I think you mean the Iwahori or Cartan decomposition (depending on what your $K$ is), not the Bruhat decomposition (which corresponds to the non-compact choice of $K = B$ a Borel subgroup). $\endgroup$
    – LSpice
    Commented Jun 10, 2019 at 3:14
  • $\begingroup$ @LSpice I think I was thinking about Bruhat decompositions for affine Lie groups, where Borels are compact, but I don't really know. $\endgroup$
    – Will Sawin
    Commented Jun 10, 2019 at 4:38

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