Is there an example of a number field $K$ for which the genus field of $K$ is contained strictly in the Hilbert class field of $K$?

7$\begingroup$ Any quadratic field with class group that is not an elementary $2$group, the canonical example probably being $\mathbb{Q}(\sqrt{23})$. $\endgroup$ – Aurel Jan 22 '18 at 12:43

$\begingroup$ @Aurel: Why not turn your comment into an answer? $\endgroup$ – GH from MO Jan 22 '18 at 22:23

$\begingroup$ @GHfromMO I wasnt't sure the question was going to be considered research level. But sure, why not :) $\endgroup$ – Aurel Jan 22 '18 at 22:32

$\begingroup$ @Aurel: Thanks. Perhaps adding a bit of explanation (class field theory etc.) might help the OP. Strictly speaking, the question is not of research level, but it is certainly of "graduate school level", so I think it is appropriate here. $\endgroup$ – GH from MO Jan 22 '18 at 22:57
Let $K$ be a quadratic field with class group $\mathrm{Cl}(K)$ such that $\mathrm{Cl}(K)\neq \mathrm{Cl}(K)[2]$. Since the Galois group of the genus field is isomorphic to $\mathrm{Cl}(K)[2]$ and the one of the Hilbert class field to $\mathrm{Cl}(K)$, this provides an example.
The canonical example is probably $K=\mathbb{Q}(\sqrt{23})$: it has class number $3$, and its Hilbert class field $H$ is generated over $K$ by a root of $x^3x1$. The field $H$ is Galois over $\mathbb{Q}$, but its Galois group is $D_3$, so it is not the compositum of $K$ and a cyclic cubic extension of $\mathbb{Q}$.