2
$\begingroup$

Fix some $r >0$ and let $\mathcal P$ be a unit intensity Poisson point process on $\mathbb R^d - \mathbb B(0,r)$. Let $W_t = \cup_{s \leq t} \mathbb B(B_t,r)$ be the Brownian sausage around a Brownian motion $B_t$ started from $\mathbf 0$. Run the process until the time $\tau = \inf \{ t \colon W_t \cap \mathcal P \neq \emptyset\}$ that the sausage hits a point in $\mathcal P$.

Now, let $\mathcal P'$ be an independent unit intensity Poisson point process. Define the set $$\mathcal P'' = (\mathcal P - W_\tau) \cup (\mathcal P' \cap W_\tau).$$ So we are taking out the point that $W_\tau$ hit and putting back in $W_\tau \cap \mathcal P'$.

Is $\mathcal P''$ a unit intensity Poison point process on $\mathbb R^d$?

$\endgroup$
2
  • $\begingroup$ Note that it could happen that $W_0$ already contains more than one point of $\mathcal{P}$. Thus you cannot necessarily speak of the point that $W_\tau$ hit. $\endgroup$ Dec 3, 2017 at 19:25
  • $\begingroup$ Thanks. I fixed this in the question statement by clearing out an empty ball around the origin. $\endgroup$ Dec 3, 2017 at 21:53

1 Answer 1

-1
$\begingroup$

See the appendix of this paper on the Brownian frog model: https://arxiv.org/abs/1710.05811.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.